The GCF of 28, 42 and 63 is 7.
The GCF is 7.
Half of 3 means 3 divided by 2 or 3 multipled by 1/2. Thus 1/2 X 3 = 3/2.
14 = 7 x 2
&
49 = 7 x 7
'7' is common to both numbers, so seven is the HCF ( Highest common factor).
Because all of those numbers are divisible by 21.
The greatest common factor of 8 and 28 is 4.
The greatest common factor is the highest number that divides exactly into two or more numbers.
factors of 8: 1, 2, 4, 8
factors of 28: 1, 2, 4, 7, 14, 28
The GCF for 8 and 28 is 4.
The greatest common factor of 4 and 8 is: 4.
Definition: A factor is a divisor - a number that will evenly divide into another number. The greatest common factor of two or more numbers is the largest factor that both numbers have in common.
Details of Solving the Problem
The greatest common factor of 4 is itself. Because 4 is a factor of 8 (2 x 4 = 8), and since there is no greater (larger) factor for 4 other than 4 itself, 4 is the greatest common factor of 8 and 4.
Another way to determine the greatest common factor is to find all the factors of the numbers and compare them.
The factors of 4 are 1, 2, and 4.
The factors of 8 are 1, 2, 4, and 8.
The common factors are 1, 2, and 4. Therefore, the greatest common factor is 4.
The greatest common factor can also be calculated by identifying the common prime factors and multiplying them together.
The prime factors of 4 are 2 and 2.
The prime factors of 8 are 2, 2, and 2.
The prime factors in common are 2 and 2, so the greatest common factor is 2 x 2 = 4.
Summary:
The common factors of 4 and 8 are 1, 2, and 4.
The greatest common factor of 4 and 8 is 4.
The GCF of 4 and 8 is 4.
4
4
The GCF is 4.
The greatest common factor of two and four is 2.
5y - 65xy
'5' is a common factor both numbers.
Hence 'take it out'.
5(y - 13xy)
'y' is a common factor to both terms, so take it out too!!!!
5y(1 - 13x)
Done Factored!!!!!
20x^2 + 22x - 12
Since '2' is a common factor
Then
2(10x^2 + 11x -6)
To factor the bracket bit , we write down all the factors of '10' & '6'
Hence
10 ; 1,2,5,10,
6 ; 1,2,3,6.
We then select a pair of numbers from each factors to multiply together and then add/subtract to reach '11'.
They are ( 2,5) & ( 2,3)
3 x 5 = 15 & 2 x 2 = 4
15 - 4 = 11
So (2,3) & ( 2,5) are the selected factors.
Open brakets. ( 5x 2)(2x 3)
To select the signs, we note that '6' is a minus '-6' , so the signs are differen(+/-).
We also note that 11x is positive (+) , so the larger multiple is the positive multip;le and the small is the negative.
Hence
(5x - 2)(2x + 3)
Overall it is
2(5x - 2)(2x + 3)
x2 - 5x - 66 is a quadratic expression that factors out to (x - 11)(x + 6)
Remember both 16 & 25 are squared numbers.
16 = 4^2 & 25 = 5^2
Hence we can write
(4x)^2 - (5y)^2
Remember two squared terms with a NEGATIVE Between them will factor.
( 4x - 5y)(4x + 5y)
Note the difference signs.
NNB Two squared terms with a positive (+) between them DOES NOT factor.
In one sense, the opposite of the GCF could be the least common factor, but the least common factor of any set of positive integers is 1, so it's not very interesting.
They are elements of an infinitely large set of numbers of the form 100000*k where k is an integer.