8 Ft it cant be 8 it is ether 7.5 ft or 10 ft or 12 ft or 15 ft
radius of curvature is double of focal length. therefore, the formula is: 1/f = (n-1)[ 1/R1 - 1/R2 + (n-1)d/nR1R2] here f= focal length n=refractive index R1=radius of curvature of first surface R2=radius of curvature of 2nd surface d=thickness of the lens using this, if you know rest all except one, then you can calculate that.
35mm
The image of the star will be 67.5 cm from the mirror because focal length is the raidus of curvature multiplied by 2 or (2)(C). So, therefore, 150 / 2 will give the focal length which would also be the answer.
the radius and ulna along its length
A blood vessel's radius has a larger effect on the body than the vessels length because more blood can flow through a larger blood vessel. A change in the radius will have more of a affect.
Radius of curvature divided by tube diameter. To get the radius of curvature, imaging the bend in the tube is a segment of a circle, the radius of curvature is the radius of that circle.
radius of curvature = 2Focal length
12 ft
Assume that the height of the segment is h, the chord length is c and the radius is r then: r2=(r-h)2+(c/2)2 (We join two radii to the two ends of the chord then extend the height of the segment to the center of the circle in which the segment is inscribed so this height will bisect the chord and you use the pythagorean theorem to find the radius)
The focal length of a convex mirror is half of its radius of curvature.
There is a specific formula for finding the radius of a curvature, used often when one is measuring a mirror. The formula is: Radius of curvature = R =2*focal length.
The radius of curvature and the focal length mean the same so the radius of curvature is also 15 cm.
NO it cannot be. Because radius of curvature is given by the expression R = 2 f
The focal length of a concave mirror is about equal to half of its radius of curvature.
yes
The Center of curvature is 2 times the focal length. By the way this is a physics question.
R = 2f