No, it is a straight line passing through the origin.
Not actually the speed but the velocity ,slope is described as dy/dx and in the position time graph position is on y-axis&time on x-axis,so slope=dx/dt which is equal to velocity
Constant speed is represented on the graph as any straight line (except vertical).
The slope of the line is the speed.
the object is not moving
Straight line
The line would be going diagnley to the right
no motion
If the x axis is time ( and the y axis distance), then the faster objects slope will be steeper.
a straight line with a positive slope
the object is not moving
It represents that the object is remaining at a fixed distance. Typically that means it is not moving.
No. It means that the object is going at a constant speed.
Straight line
It is a graph which shows the distance of an objectfrom a fixed point (the origin),only in the radial directionat different times.The importance of the second bullet is that the distance from the origin, of an object going around it in a circle, is constant. As a result the distance-time graphs of one object in rapid rotation about the origin and another object that is not moving at all will be the same!
A straight slanted slope on a velocity-time graph indicates that the object is moving with a constant acceleration.
If the line formed by the graph is straight, the speed is constant. A horizontal line would show the object as stationary.
Yes. The slope, or rate, is constant. The rate being represented is speed. If the slope is a negative constant, the object is losing distance (going towards) from the orgin at at a constant speed.
It would be anything other than a horizontal line.
The line would be going diagnley to the right
The line would be going diagnley to the right