x2-5x-24=0 [x+3] [x-8=0 x=8,-3
putting the vale
64-40-24=0 64-64=0
120 there the number
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
There are 96 boys and 120 girls at a school in grade 9. Write down the ratio of the number of boys to the number of girls in this grade 9 year.
1233338438594549854958oz
x2 - 5x - 24 = 0
(x + 3)(x - 8)
x = 8
Check it.
64 exceeds 24 by 40.
It checks.
62
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x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
x2-5x-24=0 (x+3)(x-8)=0 x=8,-3
putting the value
64-40-24=0 64-64=0
What is the interquartile range of this data?
6
7
8
9 Box-and whisker plot titled Temperatures in Celsius ranging from 12 to 48 with the five number summary from left to right 18, 25, 28, 33, and 42
If you smart do this one!
3x2 - 9 = 6x 3x2 - 6x - 9 = 0 3(x + 1)(x - 3) x = -1, 3 The answer is 3. Check it. 27 - 9 = 18 It checks.
81
(92 x 2) - (9 x 2) = 162 - 18 = 144 The number is therefore 9.
No 38 is not a square number.
When you square a real number the answer is positive,
31 squared = 961. 32 squared = 1,024. The first prime number that is greater than 32 is 37. Therefore, 37 is the first prime number whose square exceeds 1,000.
The problem can be written as3x2 = 6x + 9x is the number we want to findSolution:x2 = 2x + 3x2 - 2x - 3 = 0(x-3)(x+1) = 0x = -1, 3
3x2 - 9 = 6x 3x2 - 6x - 9 = 0 3(x + 1)(x - 3) x = -1, 3 The answer is 3. Check it. 27 - 9 = 18 It checks.
Russia just barely exceeds that number, and it's the only one.
no
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
If we were to graph the number it would be: y = x If we were to graph the square it would be: y = x² The difference would be: f(x) = x - x² You want to maximize this difference, so take the derivative: f'(x) = 1 - 2x Then set it to zero: 0 = 1 - 2x Add 2x to both sides: 2x = 1 Divide both sides by 2: x = ½ Answer: ½ is the number that most exceeds its square.
81
d no is "6"
When you walk, you advance a certain number of meters, not square meters.
"7" is the number because its square root is "49" & 49+7=56
6