Yes, in a series circuit, the sum of the voltage drops across each component equals the total voltage supplied by the voltage source. This principle is a manifestation of Kirchhoff's Voltage Law, which states that the total voltage around a closed loop must equal zero. Therefore, the voltage provided by the source must equal the combined voltage drops across all components in the circuit.
A voltage or current source in series with a circuit breaker or fuse in series with a switch in series with a light bulb.
The Thevenin's equivalent circuit consist of a voltage source in series with a resistor.
multiplies source voltage, two 12v dc batteries in series become a 24v circuit; also multiplies resistence
no
depend on the R value(s) because V Source = Sum of individual voltage across each R in the series so if R in the series are equal value, then their V are the same and their V total will be equal of the V Source
A voltage or current source in series with a circuit breaker or fuse in series with a switch in series with a light bulb.
No. The total voltage drop around a series circuit, per Kirchhoff's voltage law, is zero. However, it is true that the total voltage drop of all of the components except the battery is equal and opposite to the voltage drop of the battery.AnswerInterestingly, the formal definition of electromotive force is based on Kirchhoff's Voltage Law: 'A source's electromotive force is equal to the sum of all the voltage drops around a closed loop, including the source's internal voltage drop'.Expressed as per the original answer, we could also say; 'The algebraic sum of a circuit's electromotive force and voltage drops, including the source's internal voltage drop, is zero'.
The voltage between the ends of the circuit doesn't change ... that's where the power source is connected. But when you add more items in a series circuit, the voltage across each item changes. The individual voltages across each item in the series circuit always add up to the voltage of the power source. So in general, if you add more items, the voltage across each of the original ones must drop somewhat.
In a series circuit, the voltage is divided among the components, so the highest voltage is at the beginning of the circuit. In a parallel circuit, each component receives the full voltage of the source, so the voltage is the same across all components. Therefore, the circuit with the highest voltage would be in a series circuit.
Nothing.
The Thevenin's equivalent circuit consist of a voltage source in series with a resistor.
No, voltage is not the same in parallel circuits. Voltage is constant across components in a series circuit, but in a parallel circuit, each component has the same voltage as the power source.
multiplies source voltage, two 12v dc batteries in series become a 24v circuit; also multiplies resistence
A series circuit will work if there is a closed path through which the current can pass, and a voltage source. Otherwise it won't.
Total voltage = the source. The voltage around the circuit is divided proportionally by each of the resistances in line. The current is = the source voltage divided by the sum of all the resistance.
no
depend on the R value(s) because V Source = Sum of individual voltage across each R in the series so if R in the series are equal value, then their V are the same and their V total will be equal of the V Source