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vapour density of a gas= mass of a substance at STP/mass of a hydrogen at STP

11.2= 1 gm molecule of a substance/2g

11.2*2=1 gm molecule of a substance

22.4g=1 gm molecule of a substance

22.4g occupies Lt. at STP

therefore 11.2g occupies Lt.*11.2g/22.4g=11.2Lt.

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13y ago
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3d ago

The molecular weight of a gas is twice its vapour density. Therefore, if the vapour density is 11.2, the molecular weight is 22.4 g/mol. At NTP (STP), 22.4 g of any gas occupies 22.4 L; hence, 11.2 g of the gas will occupy half that volume, which is 11.2 L.

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Q: The vapour density of a gas is 11.2 so the volume occupied by 11.2 gm of the gas at NTP is?
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