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The perimeter would be 28 meters.

Q: The width of a rectangle is 6 meters and the diagonal is 10 meters what is the perimeter?

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width=5 length=12

The width will be 30cm

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle

L + W = P/2 = 13. 13 - 7 = 6, 6/2 = 3 which is the width, making the length 10.

Related questions

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters

Diagonal = 10 meters.

The diagonal is 15.620 meters.

You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.

Perimeter of a rectangle = twice (length + width), in this case 22 m.

The width of the rectangle would be 32.5 meters.

The perimeter is 42 metres.

The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.

The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.

24 meters

320 meters squared.