Let a be the first of the three number and r the common ratio. Then
a*ar*ar2 = a3r3 = 216 = 63 so that ar = 6
Also, a + ar + ar2 = 21
Substitute ar = 6 to give 6/r + 6 + 6r = 21 or 6 + 6r + 6r2 = 21r
So that 6r2 - 15r + 6 = 0 or 2r2 - 5r + 2 = 0
2r2 - 4r - r + 2 = 0 or 2r*(r-2) - 1(r-2) = 0 or (2r-1)*(r-2) = 0 so r = 0.5 or r = 2
r = 0.5 gives the three numbers as being 12, 6, 3
and r = 2 gives 3, 6, 12.
71 + 72 + 73 = 216
71,72,73 :)
The numbers are 71, 72 and 73.
215 + 216 + 217 + 218 = 866
It is equivalent to the equation: 6m = 216
3 + 6 + 12 = 21 3 x 6 x 12 = 216
71 + 72 + 73 = 216
216 = 2x2x2x3x3x3
the sum of three consecutive numbers is 216. What are the three numbers?
71,72,73 :)
23 x 33 = 216
6 + 7 + 8 = 216 x 7 x 8 = 336Therefore, the three numbers are 6, 7 and 8.
As a product of its prime factors expressed in exponents it is: 23*33 = 216
divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73
The numbers are 71, 72 and 73.
For 216 the numbers are 70, 72 and 74. For 238 the numbers are 58, 59, 60 and 61.
x+x+1+x+2=216 3x+3=216 3x=213 71,72,73