Suppose the two numbers are x and y.
Then x + y = 58 and x - y = 16
The second equation gives x = 16 + y
Substituting this value of x into the first equation gives
(16 + y) + y = 58
or 2y + 16 = 58 or 2y = 42 which gives y = 21.
Then x = 16 + y gives x = 16 + 21 = 37
So the soln is x = 37, y = 21
Numerical equations have only numbers and symbols, while algebraic equations have variables also.
x + y = 23x - y = 7Add the equations:2x = 30x = 15Subtract the equations:2y = 16y = 8
Let the two numbers be m and n From the information given, we have two equation in two unknowns. We can solve this system using substitution. Here are the two equations. m+n=92 m-n=20 Now to use substitution, we must rewrite the second equation as m=n+20 and substitute it into the first n+n+20=92 or 2n=72 which tells us n=36 that means m=92-36 or 56. So the numbers are 36 and 56. Let's check 36+56=92 56-36=20
I think you have mistyped your question...
You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.
It is a trivial difference. If you multiply every term in the equation with rational numbers by the common multiple of all the rational numbers then you will have an equation with integers.
Numerical equations have only numbers and symbols, while algebraic equations have variables also.
Exponential and logarithmic functions are different in so far as each is interchangeable with the other depending on how the numbers in a problem are expressed. It is simple to translate exponential equations into logarithmic functions with the aid of certain principles.
Let the two numbers be m and n From the information given, we have two equation in two unknowns. We can solve this system using substitution. Here are the two equations. m+n=92 m-n=20 Now to use substitution, we must rewrite the second equation as m=n+20 and substitute it into the first n+n+20=92 or 2n=72 which tells us n=36 that means m=92-36 or 56. So the numbers are 36 and 56. Let's check 36+56=92 56-36=20
x + y = 23x - y = 7Add the equations:2x = 30x = 15Subtract the equations:2y = 16y = 8
I think you have mistyped your question...
You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.
Its harder to solve the equations with grande numbers
This is a good exercise in building and solving a set of equations. Let X and Y be the two numbers. Then you are told their sum is 36, so write; X + Y = 36 Then you are told their difference is 24, so write; X - Y = 24 Now elliminate Y by adding the two equations; 2X = 60 and X = 30 . Now you can find Y by substituting this answer into either of the two original equations to get Y = 6.
Since the sum of two numbers is 5, we have:x + y = 5 where x and y are unknowns.Since the difference of two numbers is 0.5, we have:x - y = 0.5These are the two equations we obtain from interpreting the problem:x + y = 5x - y = 0.5Combine these equations to get:2x = 5.5x = 5.5/2x = 2.75Finally, substitute the value for either of the equation and solve for y.2.75 + y = 5y = 5.00 - 2.75y = 2.25So the two numbers with the sum 5 and the difference 0.5 are 2.75 and 2.25.
x + y = 50 x - y = 16 --------------- (add the two equations to solve for x) 2x = 66 x = 33 then substitute x into one of the above equations to get y = 17
To determine the two numbers, assume the numbers to be 'x' and 'y'. Now, given that the sum of the numbers is 40. Therefore, x + y = 40 --> (A) Also, given that the difference of the numbers is 10. Therefore, x - y = 10 --> (B) Add the equations (A) and (B): 2x = 50, which gives x = 25. Use any of the equations above to determine 'y'. Using equation A: 25 + y = 40, which gives y = 15. Therefore, the numbers are 25 and 15.