Probability is defined as the number of ways an outcome can occur divided by the number of possible outcomes. For the coins, there are 4 outcomes (HH, HT, TH, TT). On the cube, there are 6 possible outcomes. The total number of outcomes is then 4*6 = 24. Since there is only 1 way to obtain HH, look at the cube outcomes. With the HH outcome, the cube would need to fall on a 4. So, there is only 1 way a HH4 can occur. Therefore the probability of getting 2 heads and a four is 1/24 or 0.04167.
The probability of tossing two heads in two coins is 0.25.
The probability is 3/8 = 0.375
3/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8
The probability is 1/16.
is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
Coins do not have numbers, there is only the probability of heads or tails.
1/4 if they are tossed only once.
If they are fair coins, it is 1/16.
Sample space for two coins tossed is: HH HT TH TT Therefore at most one head is HT TH TT or 3/4 or 0.75.
The answer depends on how many coins were tossed.
The probability of it is 37.5%. Since there are 16 possible outcomes. calculated by 2 to the power of 4. only 6 gives you the prefered results then it's a simple 6:16 ratio
The answer depends on what a winner is: 1 H?, a run of 3 H?If the winner is one H, the probability of getting exactly one winner - no more no fewer - is 5/32.
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
If they are fair coins, the probability is 0.25
pr(at most one T) = 1 - pr(not two tails) = 1 - 1/2*1/2 = 1 - 1/4 = 3/4
1/2 or 50% (1/8 prob of 0H + 3/8 prob of 1H)
When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.
The probability is 0.375
This question can be rather easily answered, as soon as outcomes 'a' and 'b' are defined.
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
The probability is 1/21/21/2*1/2=1/16, or 0.0625 or 6.25%