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two NUMBERS that are divisible by three are 6 and 9.

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โˆ™ 2009-09-19 03:02:26
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Q: Two numbers that are divisible by the number 3?
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Related questions

What number from two to ten are divisible by 495?

None of the numbers in that range are divisible by 495. 495 is divisible by 3 and 5.


Is 112343211 a prime number or a composite number?

112343211 is a composite number, not a prime number, because it is divisible by 3. A prime number is divisible by exactly two numbers, 1 and itself, while a composite number is divisible by more than two numbers.


What are the divisibility rules for 1 2 3 4 5 6 9 and 10?

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.


How many two digit numbers are divisible by either 3 or 5?

How many two digit number are divisible by 5


Which kind of number is divisible by 2 - odd numbers - all counting numbers - even numbers - whole numbers?

Only even numbers are divisible by two. If you have an odd number, for example 3, and divide by two, you will get 1 with a remander of 1.


Are all even numbers divisible by 6?

Not all even numbers are divisible by 6. These numbers are not evenly divisible by 6: Any number smaller than 6. Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.


What numbers are not divisible by 6?

These numbers are not evenly divisible by 6: Any number smaller than 6. Any odd number (not divisible by 2). Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.


How do you explain that even without listing all the factors of a number it is easy to tell that they are composite numbers?

To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.


What numbers are divisible by 2 3 and 7?

The smallest number that can be divisible by these three numbers is 42. If 42 is multiplied by 2, 3, 7, or any number divisible by only one of those numbers then that number as well will be divisible by 2, 3, and 7.


What numbers divisible by 2 and 3 are also divisible by what number?

6


What counterexample to the statement all odd numbers are divisible be 3?

5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.


How many two digit numbers divisible by neither 3 nor 5?

48.The first two digit number is 10, the last two digit number is 99, so there are 99 - 10 + 1 = 90 two digit numbers→ 10 ÷ 3 = 31/3 → first two digit number divisible by 3 is 4 x 3 = 12→ 99 ÷ 3 = 33 → last two digit number divisible by 3 is 33 x 3 = 99→ 33 - 4 + 1 = 30 two digit numbers divisible by 3→ 10 ÷ 5 = 2 → first two digit number divisible by 5 is 2 x 5 = 10→ 99 ÷ 5 = 194/5 → last two digit number divisible by 5 is 19 x 5 = 95→ 19 - 2 + 1 = 18 two digit numbers divisible by 5→ 30 + 18 = 48 two digit numbers divisible by 3 or 5 OR BOTH.The numbers divisible by both are multiples of their lowest common multiple: lcm(3, 5) = 15, and have been counted twice, so need to be subtracted from the total→ 10 ÷ 15 = 010/15 → first two digit number divisible by 15 is 1 x 15 = 15→ 99 ÷ 15 = 69/15 → last two digit number divisible by 15 is 6 x 15 = 90→ 6 - 1 + 1 = 6 two digit numbers divisible by 15 (the lcm of 3 and 5)→ 48 - 6 = 42 two digit numbers divisible by 3 or 5.→ 90 - 42 = 48 two digit numbers divisible by neither 3 nor 5.

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