Two planes approach each other head on and Each at a speed of 785kmhr and spot each other 11km apart how much time to take evasive action?


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We have to assume that the 785 km/hr is the speed measured by an observer on the ground, NOT the closing speed. The closing speed is (785 x 2) = 1,570 km/hr. If the impending catastrophe first attracts their attention when they are 11 km apart, then the distance between them at that instant represents 11/1570 = 0.007 of an hour = 25.22 seconds (rounded)