It is correct only if the object in question is subject to a constant acceleration.
The accleration must be constant.
You subtract the initial velocity from the final velocity and divide by the time interval.
If s = displacement, u = initial velocity, a = acceleration, t = time. Then s = ut + 1/2at2 Be careful to keep units consistent
Half Km - not sure-
I am assuming the initial speed is 6.2 m/s Let upward motion be positive! Gravity decreases the speed by 9.8 m/s each second Acceleration due to gravity = -9.8 m/s each second (negative because gravity accelerates objects downward) Find time to reach the top of the path! Final velocity at the top = 0 m/s Initial velocity = 6.2 m/s Final velocity = Initial velocity + acceleration * time Time - = (final velocity - initial velocity) ÷ acceleration Time = (0 - 6.2) ÷ -9.8 = 0.633 seconds (to reach top) The path is symmetrical. 0.633 seconds to reach top and 0.633 seconds to reach glove again. Total time = 12.66 seconds
It is acceleration. The difference between final velocity and initial velocity, divided by the time is the AVERAGE acceleration. Remember, though that velocity is a vector. So if you are going round in a circle at a constant speed, your direction of motion is changing continuously and so you are always accelerating!
You can't.You only know what half the sum of (initial + final) is, (it's the average), but you don't know what the initial and final are.
If you have a particle with constant acceleration, and you add the initial and final velocities and then divide them by two, what you get is the average velocity of the particle in that period of time.
Both the gliders will be travelling at exactly the same speed as the initial velocity but in opposite directions.
Is this a question? or a statement that you are unsure of? Well anyways, this would be correct if acceleration was a constant but if acceleration is not a constant, the (not-constant) acceleration would change the rate of velocity and thus that statement/question would be false.
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That's going to depend on the directions of each of the two initial velocities. It's also going to depend on who measured the initial velocities, where he was standing, how he was moving, and with respect to what else, etc.
Initial velocity is 10 m/s in the direction it was kicked. Final velocity is 0, when friction and air resistance finally causes it to come to a halt.
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
No, It is the average velocity.
If you know average speed then you cannot determine the acceleration: the very nature of being a average hides all the increases and decreases in speed which are the accelerations (technically, acceleration is change of speed in a direction). All average speed tells you is the constant speed at which you require to travel to cover the given distance in the given time; as the speed is constant, the acceleration is zero.
There are several definitions. not just one. Average velocity in a direction = Average displacement (distance) in that direction/time Instantaneous velocity in a direction = derivative of displacement in that direction with respect to time Average velocity in a direction = Initial velocity in that direction + Average acceleration in that direction * time Instantaneous velocity in a direction = Definite integral of acceleration in that direction with respect to time, with initial velocity at t = 0 Then there are others in which time is eliminated.
It is usually a continually varying amount which depends on its initial velocity - when it is pitched or hit - and other forces such as the acceleration due to gravity, aerodynamic drag and so on.