You could draw in the two diagonals (from corner to opposite corner). You could draw two perpendicular lines to develop four squares inside the existing square. You could draw three parallel lines to develop four equally-sized rectangles within the square.
The answer is 4! which is equal to 1 x 2 x 3 x 4.
Theoretical probability is the probability of an event when all outcomes are equally likely. With theoretical probability, you determine the probability by dividing the number of ways the event can occur by the total number of equally likely outcomes.
There are 7 letters, but three 'o's are indistinguishable, so there are 7! ÷ 3! ways = 840 ways. If the 'T' and the 't' are also considered to be indistinguishable (that is ignoring the case of the letters; making "Toronto" and "toronTo", etc the same), then the number of ways is 7! ÷ (3! x 2!) ways = 420 ways. ! after a number means the factorial of the number which is the product of all numbers less than or equal to the number, and greater than or equal to 1. Thus: 7! = 7 x 6 x 5 x 4 x 3 x 2 x 1. 3! = 3 x 2 x 1 2! = 2 x 1 0! is defined to be 1.
This is a question of permutations; the answer is equal to the factorial of 5 (number of digits) divided by the factorial of 3 (number used in each selection), written 5! / 3!. This equals 120 / 6, or 20 ways.
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.
divide a square into eighths
Combined a multiplication sign with a plus sign.
Draw a square and divide it into six equal rectangles, for example: ................................... ... ------------------ ... ... | . | . | . | . | . | . | ... ... | . | . | . | . | . | . | ... ... | . | . | . | . | . | . | ... ... | . | . | . | . | . | . | ... ... | . | . | . | . | . | . | ... ... | . | . | . | . | . | . | ... ... | . | . | . | . | . | . | ... ... ------------------ ... ...................................
5
yes
Yes you can, but you have to use zig zag lines. Using straight lines there are only four ways to divide a square into two equal parts (along the lines of symmetry).
Only once, there will only be eights parts however you divide it.
with a knife... lol... sorry couldn't help it
0.5
By cutting along its lines of symmetry
There are an infinite number of points on two adjacent sides of a square which can be joined to the diagonally opposite point, so there is an infinite number of ways of halving a square.
It can be done easily in an infinite number of ways. Select any point on the perimeter of the square and cut from there, through the centre of the square, to the opposite perimeter. All in a straight line.