x^3 + 7x^2 + 17x +15
-23
2x2-4x+5 divided by x-1 Quotient: 2x-2 Remainder: 3
4x - 3 = 5 4x = 5 + 3 4x = 8 x = 8/4 x = 2
x-4x=5 (1)x-(4)x=5 (-3)x=5 x= 5/(-3) x= -5/3
Dividend: 4x^4 -x^3 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
If a polynomial is divided by x - c, we can use the Remainder theorem to evaluate the polynomial at c.The Remainder theorem:If the polynomial f(x) is divided by x - c, then the remainder is f(c).Example:Given f(x) = x^3 - 4x^2 + 5x + 3, use the remainder theorem to find f(2).Solution:By the remainder theorem, if f(x) is divided by x - 2, then the remainder is f(2).We can use the synthetic division to divide.2] 1 -4 5 32 -4 2__________1 -2 1 5The remainder is 5, so f(2) = 5Check:f(x) = x^3 - 4x^2 + 5x + 3f(2) = (2)^3 - 4(2)^2 + 5(2) + 3 = 8 - 16 + 10 + 3 = 5
5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5
5-4x=x-35-4x+4x=x-3+4x (adding 4x on both side)5=5x-35+3=5x-3+3 (adding 3 on both side)8=5xx=8/5
-1
5 + 4x - 7 = 4x + 3 - x (eliminate alike terms in both sides)5 - 7 = 3 - x (leave the variable alone by itself)5 - 7 - 3 = 3 - 3 - x-5 = -x (multiply both sides by -1)5 = x
(4x^4 - x³ + 17x² + 11x + 4) ÷ (4x + 3) = x³ - x² + 5x - 1 remainder 7. Do the division via long division, looking at the highest power of x in the dividend: _________________x³ ___- x²_ + 5x - 1 ________----------------------------------- 4x + 3 | 4x^4 - x³ + 17x² + 11x + 4 _________4x^4 + 3x³ _____________________ ← x³(4x + 3); x³ in the quotient _________-------------- _______________- 4x³ + 17x² ______________ ← subtract and bring down next term (+ 17x²) _______________ -4x³ __ -3x² ______________ ← -x²(4x + 3); - x² in the quotient _______________--------------- ______________________ 20x² + 11x ________ ← subtract and bring down the next term (+ 11x) ______________________ 20x² + 15x ________ ← 5x(4x + 3); + 5x in the quotient ______________________ -------------- ______________________________ -4x + 4 ____ ← subtract and bring down the next term (+ 4) ______________________________ -4x - 3 _____ ← -1(4x + 3); -1 in the quotient ______________________________ -------- ___________________________________ 7 ______ ← subtract; no more terms to bring down, this is remainder.
The equation 4x + 5 = 2 has the solution 4x = -3 and x = - 3/4 (minus 3/4).
4x - 3 = 17 4x = 17 + 3 4x = 20 x = 20 / 4 x = 5