There are an infinite number of groups of three that all average 125.
Here are a few:
124, 125, 126
120, 125, 130
100, 125, 150
25, 125, 225
1, 125, 249
3, 73, 299
7, 183, 185
1, 2, 372
.
.
etc.
124, 125 and 126
The average is the sum of the numbers in the set divided by the number of numbers in the set. In this case it is (125+143+134)/3=134.
There can only be 3 of them because as a product of its prime factors: 5*5*5 = 125
They are: .1+.02+.005 = .125
They are: 2*5*11 = 110
125
They are: 25+36+64 = 125
1 x 375, 3 x 125, 5 x 75, 15 x 25.
To get the simple average of a series of numbers, you add the numbers up and divide by however many numbers there were. For example, the average of 2, 3 and 4 is the sum of the numbers (which adds up to 9) divided by 3 (because there are three numbers). So the average is 9/3 = 3.
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
125
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