Stereo system
Best way to approach this, convert dimensions to centimeters, then Volume calculated will be in cubic centimeters. 1 cubic centimeter = 1 milliliter.750mm = 75 cm, 2960 mm = 296 cm. Volume = pi * (75 cm)2 * (296 cm) = pi * 1665000 cm3 = approx 5230752 cm3 = 5230752 mL = 5230.752 liters
The volume of a cylinder with a base of 75 and height of 9 is: 39,800 cubic units.
If your newborn baby is measured and you're told that she's 75 cm tall, then that's a pretty good indication that she is 75 cm long. I say 'newborn' and 'long' because she is most likely not standing up and running around. 75 cm is only 29.5 inches ... about 21/2 feet.
Volume of a pyramid = 1/3*base area*height Volume = 250,000 cubic mm
15g/cm^3
The volume is already stated. 75 cm3
3.9 cm3 (cubed)
There are 75 millilitres in 75 cm3
Best way to approach this, convert dimensions to centimeters, then Volume calculated will be in cubic centimeters. 1 cubic centimeter = 1 milliliter.750mm = 75 cm, 2960 mm = 296 cm. Volume = pi * (75 cm)2 * (296 cm) = pi * 1665000 cm3 = approx 5230752 cm3 = 5230752 mL = 5230.752 liters
The actual density of Oak Wood is about .75 g/cm3.
about .75 g/cm3
The odds are 75%
1 cm3 = 1 ml 1 l = 1000 ml = 1000 cm3 ⇒ 0.75l = 0.75 x 1000 cm3 = 750 cm3
ans:you cannot workout the density of a mass simply by knowing its mass; you would also have to know its volume.example: what is the density of something that is 25g and is of volume 1m squared?Its 0.025kg/m^2
That depends on the density (density = mass / volume). If it is water then the volume would be 75 ml or 75 cu cm.
75 mL = 75 cc
Finding the basicity of an acid: The concentration of the unknown acid must be the same as that of the base. You will need: 1 polystyrene cup 2 250ml beaker 1 laboratory thermometer The unknown acid (aq.) with the same concentration as NaOH NaOH (aq.) Steps: 1. Mix an equal volume of the base, using NaOH (aq.) and the unknown acid, both of equal concentration. (e.g. 50 cm3 NaOH and 50 cm3 unknown acid; total volume of water is 100 cm3). 2. Measure and record the highest temperature change using the laboratory thermometer. 3. Next, you need to mix another volume of NaOH (aq.) and half the volume as NaOH of the unknown acid. (e.g. 50 cm3 NaOH and 25 cm3 unknown acid). Since total volume of water in step 3 is only 75 cm3, have to add 25 cm3 to make the total volume of water 100 cm3 so as to make both volumes of water used the same. So have to add 25cm3 to either NaOH or the unknown acid before mixing them. 4. Repeat step 2. 5. If the temperature rise of both is the same, then the unknown acid is dibasic. If the temperature rise of one is half of the one, then the unknown acid is monobasic. Yep, this is what I got from my senior, hope it's correct!