Kb=1.62 * 10-12
They are both the same, short for kilobytes.
There are 1,000 bp in 1 Kb.
NaCN doesn't really have a pKa. In water it becomes Na^+ and CN^-. The CN^- is a base so it will have a Kb and pKb. If you want the pKa of the conjugate acid (HCN), you can find that from 1x10^-14/Kb.
cannot..because KB only can partially ionize to give OH+ while Ka only will partially ionize to give H+..
kb is the Dissociation Constant for Bases.
Kb = 1.8 x 10-5 (apple x)
Kb = 3.8 10-10
Kb = 55 It is a very strong base therefore it completely dissociates.
There are 8 bits to 1 byte. One K represents 1,024 bytes. Therefore, 1 KB is equal to the following: 8 x 1,024 = 8,192 bits
They are both the same, short for kilobytes.
1 kb = 1,000 bp
KB = Kilo bytes which is equal to 1,000 bytes :)
There are 1,000 bp in 1 Kb.
At half titration pH=pKa (you need the pH from the graph of your titration, y axis) ph = pKa + log (base/acid) 10^-pKa = Ka Kw=Ka*Kb Kb=Kw/Ka Ka = Kw/Kb
The constants Ka and Kb relate to the relative strengths of series of acids or bases by being proportional. The higher the Ka or Kb value, the stronger the acid or base.
The strength of an acid is expressed by its Ka value (acid 'equilibrium' constant) or its derivative pKa value ( pKa=-log10[Ka] )The relation with the strength of the conjugate base, (Kb , pKb values) is as follows:Ka * Kb = 1.0*10-14 at 25oCpKa + pKb = 14.00 at 25oC
The binary system uses forces of two base, so 1kB = 2^10 = 1024 Byte hence; 1MB = 2^10 KB= 1024 KB and 1GB = 2^10 MB = 1024 MB The answer to your question is: 1GB = 2^10 MB = 2^10 (2^10 KB) = 2^20 KB 1 GB = 1,048,576 KB