There are infinitely many sets that will satisfy the requirements.
Even if restricted to integer values there are many. Two possibilities are:
16, 28, 28, 30, 32, 34
17, 27, 28, 30, 31, 35
(1, 5, 97, 99, 100, 100) The mode is 100. The median is 98. The mean is 67.
100,100,100,100,100,100
It is best shown by an example. Hence is a set of numbers. 2,3.6.8. 10, 10, 10. 11.17. 21.23. First of all place then in RANK order. (That is lowest to highest ; already done). RANGE ; The difference between the highest and lowest values Hence 23 - 2 = 21 The Range!!!!! MODE ; The term that occurs most frequently, In this case it is '10' because it occurs three times. all the rest only occur once. MEDIAN : The absolute middle value. Since there are eleven terms, we require the sixth term. So counting along six places it is '10'. MEAN : It is the sum of all the terms divided by the number of terms. Hence (2+3+6+8+10+10+10+11+17+21+23) / 11 = 121/11 = 11 The mean!!!! A Calculator in Statistical (SD) mode will do all of this!!!!! Hope that helps!!!!
There are five values with one missing. The original set had six values with a mean of 5, which means that the members of the set added up to thirty. The values we have total 19, the missing value is 11.
1
(3, 4, 6, 8, 9)
There are at least 7 such sets, among them, 1,2,6,6,6,7,7.
4 4 6 6 10
There are infinitely many possible solutions. Even if you limit your answer to integers, there are over a hundred. One possible answer {16, 26, 28, 30, 34, 34}
The mean (average) may often be confused with the median, mode or range. The mean is the arithmetic average of a set of values, or distribution; however, for skewed distributions, the mean is not necessarily the same as the middle value (median), or the most likely (mode). For example, mean income is skewed upwards by a small number of people with very large incomes, so that the majority have an income lower than the mean. By contrast, the median income is the level at which half the population is below and half is above. The mode income is the most likely income, and favors the larger number of people with lower incomes. The median or mode are often more intuitive measures of such data.Nevertheless, many skewed distributions are best described by their mean -- such as the exponential and Poisson distributions.For example, the arithmetic mean of six values: 34, 27, 45, 55, 22, 27 is the sum 210 divided by 6, which is 35.
(1, 5, 97, 99, 100, 100) The mode is 100. The median is 98. The mean is 67.
12,18,190,13,13,15,1,78,1,6,6,2,
There are six numbers, so the median is the mean of the third and fourth (when ordered). Median = (14+27)/2 = 41/2 = 20.5
100,100,100,100,100,100
I think this is impossible? 3.5 4.5 5.5 6.5 7.5 8.5 are 6 numbers that add to 36, have a a mean of 6 but a range of only 5.
(3, 4, 5, 7, 8, 9)
12.1667