displacement = (final velocity square + initial velocity sq. )/ 2 * acceleration
FIRST EQUATION OF MOTION a=(v-u)/t at = v-u => v-u = at => v= u + at (1) This is Newton's First equation of motion. As you can you see, we can use this equation to calculate the velocity of a body which underwent an acceleration of a m/s for a time period of t seconds, provided we know the initial velocity of the body. Initial velocity i.e. u is the velocity of the body just before the body started to accelerate i.e. the velocity at t=0. SECOND EQUATION OF MOTION velocity = distance traveled / time taken average velocity = (u+v)/2 .: (u+v)/2 = s/t s = [(u+v)/2]t From equation (1) we have v=u+at, substituting this in the above equation for v, we get s = [(u+u+at)/2]t => s = [(2u+at)/2]t => s = [(u + (1/2)at)]t => s = ut + (1/2)at2 - (2) This is Newton's second equation of Motion. This equation can be used to calculate the distance traveled by a body moving with a uniform acceleration in a time t. Again here, if the body started from rest, then we shall substitute u=0 in this equation THIRD EQUATION OF MOTION We start with squaring equation (1). Thus we have v2 = (u+at)2 => v2 = u2 + a2t2 + 2uat => v2 = u2 + 2uat + a2t2 => v2 = u2 + 2a(ut + (1/2)at2) now, using equation 2 we have => v2 = u2 + 2as - (3) As you can see, the above equation gives a relation between the final velocity v of the body and the distance s traveled by the body. Thus, we have the the three Newton's equations of Motion as 1) v= u + at 2) s = ut + (1/2)at2 3) v2 = u2 + 2as
1st equation....................
An object has an initial velocity of 20 ms-1. The object accelerates uniformly for 10 seconds and its final velocity is 45 ms-1. Calculate the acceleration of the object. Answer
Step 1
Gather the information, including the quantity you are asked to find.
initial velocity u = 20 ms-1
final velocity v = 45 ms-1
time t = 10 s
acceleration a = ?
Step 2
Check the units. In this problem all of the units are correct and, as there are no multiples like mm or km, there is no need to change any units.
Step 3
Select the correct relationship. Look at the symbols, what relationship contains the four symbols u, v, t, and a?
v = u + at
Step 4
Carefully substitute the numbers one at a time.
45 = 20 + a × 10
Step 5
Carry out the calculation - you can do this at the side of the page or on your calculator.
45 - 20 = a × 10
25 = a × 10
a = 25/10
= 2.5
Step 6
Write down your answer, including the correct unit.
acceleration = 2.5 ms-2
2nd equation
Question
An electron, released from rest, accelerates uniformly over a distance of 30 mm and reaches a velocity of 600 km s-1. Calculate the acceleration of the electron.
u = 0 ms-1
s = 30 mm = 0.03m
v = 600 kms-1 = 6 × 105 ms-1
a = ?
v2 = u2 + 2as
(6 × 105)2 = 02 + 2 × a × 0.03
a = 6.0 × 1012
Acceleration = 6.0 × 1012 ms-2
3rd equation
uestion
A ball dropped is down a well and hits the water after 4 s. How far is the surface of the water below the top of the well?Answer
u = 0 ms-1
t = 4 s
s = ?
a = g = 9.8 ms-2 (value from data)
s = ut + ½ at2
0 × 4 + ½ × 9.8 × 42
= 78.4
Depth of water surface = 78.4 m
1) v=u+at
2) s=ut+(1/2)at2
3) v2-u2=2as
If you are talking about newton's second law of motion, the three things are : force, mass, and acceleration
The "equations of motion" are statements that describe motion. They would not be of much use if the very thing they're used to describe caused them to change. I'll say they don't.
( t = I a ) Rotational motion and centripetal acceleration. This is defined by its equations of motion.
Yes it is because in the case always the velocity is tangential and it's displacement can be found by Newton's equations of motion
( 1 ) rectilinear motion which is motion along a straight line( 2 ) curvilinear motion which is motion along a curve or in a circle( 3 ) oscillatory motion which is motion back and forth
Individuals firing missiles will use Projectile Motion equations to determine where the missile will hit, so they can fire them with the correct trajectory at the intended target. An i-phone game, Angry Birds, uses projectile motion as well.
means motion of equation
One can solve equations of motion by graph by taking readings of the point of interception.
4
The "equations of motion" are statements that describe motion. They would not be of much use if the very thing they're used to describe caused them to change. I'll say they don't.
Equations of kinematics or equations of motion can not be used when the body is not accelerating or is moving with a constant velocity.
Constant acceleration motion can be characterized by motion equations and by motion graphs. The graphs of distance, velocity and acceleration as functions.
Sir Issac Newton.
( t = I a ) Rotational motion and centripetal acceleration. This is defined by its equations of motion.
Main application of rectilinear motion in the field of science is to find the motion, position and distance of an object. It can also be used to make comparison between the parameters of object in real field, relative velocity, relative motion and acceleration of an object can be determined. Thus, using the equations of rectilinear motion, one can take advantage in the field like factories of machinery where the terms like motion, acceleration, position of object are main functioning concern. Practically, to design something on the basis of motion, acceleration , etc , the equations of rectilinear motion are of great importance.
Yes it is because in the case always the velocity is tangential and it's displacement can be found by Newton's equations of motion
u = initial velocity in newtons equations of motion.
equations of motion, study of light, laws of motion, invention of calculus method, specially differentiation and integration