same question i am asking i hope some one will see this question and improve this answer by putting in the divisors of that number
33550336 = 212*8191 So its factors are of the form 2m and 2n*8191 where 0 ≤ m,n ≤ 12. Their sum is (1 + 8191)*(20 + 21 + 22 + ... + 212) = 8192*(213 - 1)/(2 -1) = 67100672 This includes the factor 33550336 itself, so the sum of the proper factors is 67100672 - 33550336 = 33550336. Therefore the number is perfect.
The fifth perfect number is 33,550,336.
2,4,8 (1 and 16 are divisors too, but the number and 1 are always divisors)
Sum of divisors = 91.
12 has six divisors.
it is 12345667890
33550336 = 212*8191 So its factors are of the form 2m and 2n*8191 where 0 ≤ m,n ≤ 12. Their sum is (1 + 8191)*(20 + 21 + 22 + ... + 212) = 8192*(213 - 1)/(2 -1) = 67100672 This includes the factor 33550336 itself, so the sum of the proper factors is 67100672 - 33550336 = 33550336. Therefore the number is perfect.
A number is considered perfect if it is equal to the sum of all its positive factors/divisors, excluding itself. These are the first few perfect numbers: * 6 * 28 * 496 * 8128 * 33550336 * 8589869056A perfect number is a positive integer that is equal to the sum of its positive divisors, excluding the number itself. An example 1+2+3=6 and 1x2x3=6
It is 33550336
Yes, there is. It is 33550336.
yes. 33550336 is in fact a perfect number. i know this because on a math problem it asks "show that each number is perfect", so it must be perfect. :) ur welcome!
The fifth perfect number is 33,550,336.
6, 28, 496, 8128, 33550336
Divisors are used to divide numbers.
2,4,8 (1 and 16 are divisors too, but the number and 1 are always divisors)
Sum of divisors: 1728.
Sum of divisors: 980.