The factors of 12 are: 1, 2, 3, 4, 6, and 12.
The prime factors of 12 are: 2 and 3.
The factors of 15 are: 1, 3, 5, and 15.
The prime factors of 15 are: 3 and 5.
The factors of 18 are: 1, 2, 3, 6, 9, and 18.
The prime factors of 18 are: 2 and 3.
The factors of 18 are:
1, 2, 3, 6, 9, 18
2 and 3 are prime.
The factors of 35 are:
1, 5, 7, 35
5 and 7 are prime.
The factors of 45 are:
1, 3, 5, 9, 15, 45
3 and 5 are prime.
The factors of 74 are:
1, 2, 37, 74
2 and 37 are prime.
The factors of 88 are:
1, 2, 4, 8, 11, 22, 44, 88
2 and 11 are prime.
The factors of 92 are:
1, 2, 4, 23, 46, 92
2 and 23 are prime.
The factors of 18 are: 1, 2, 3, 6, 9, and 18.
The prime factors of 18 are: 2 and 3.
The factors of 81 are: 1, 3, 9, 27, and 81.
The only prime factor of 81 is: 3.
The prime factorisation is 183545748892 = 2^2*11*37*112743089.There are 24 factors in all.
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, and 24.The prime factors of 24 are: 2 and 3.The factors of 45 are: 1, 3, 5, 9, 15, and 45.The prime factors of 45 are: 3 and 5.
if you find the prime factors it makes the number easier to multiple. first make prime factor trees for each of the numbers. i did 18x15. 18 could have 3, 3 and 2 and 15 could have 3 and 5. then the sum could be: 5x2=10x3=30x3=90x3=270 hope this helps. if you are not sure, look up prime factor trees first.
Common factors of 12, 15, and 18 are: 1 and 3.
The factors of 15 are 1, 3, 5, and 15.The factors of 18 are 1, 2, 3, 6, 9, and 18.The factors of 12 are 1, 2, 3, 4, 6, and 12.The common factors of 15, 18, and 12 are 1 and 3 .
2 x 2 x 3 x 3 = 36 3 x 3 x 5 = 45
Prime factors of 18 are 2 and 3 Prime factors of 15 are 3 and 5
The prime factors of 15 are 3 and 5. The prime factors of 18 are 2 and 3. The highest power of each of these is 1.
Factors for 12 are: 1, 2, 3, 4, 6, 12 Factors for 18 are: 1, 2, 3, 6, 9, 18 Out of these 2 and 3 are the prime factors.
No, 12 and 18 are not coprime. Their common factors are 2, 3, and 6.
The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, and 24.The prime factors of 24 are: 2 and 3.The factors of 45 are: 1, 3, 5, 9, 15, and 45.The prime factors of 45 are: 3 and 5.
if you find the prime factors it makes the number easier to multiple. first make prime factor trees for each of the numbers. i did 18x15. 18 could have 3, 3 and 2 and 15 could have 3 and 5. then the sum could be: 5x2=10x3=30x3=90x3=270 hope this helps. if you are not sure, look up prime factor trees first.
Common factors of 12, 15, and 18 are: 1 and 3.
The factors of 12 are: 1, 2, 3, 4, 6, and 12.The prime factors of 12 are: 2 and 3.The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, and 36.The prime factors of 36 are: 2 and 3.
The factors of 18 are: 1, 2, 3, 6, 9, and 18.The prime factors of 18 are: 2 and 3.The factors of 39 are: 1, 3, 13, and 39.The prime factors of 39 are: 3 and 13.The factors of 45 are: 1, 3, 5, 9, 15, and 45.The prime factors of 45 are: 3 and 5.
The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, and 36.The prime factors of 36 are: 2 and 3.The factors of 45 are: 1, 3, 5, 9, 15, and 45.The prime factors of 45 are: 3 and 5.
Prime factors of 15: 3 and 5 Prime factors of 18: 2 and 3 squared So LCM: 2*3*3*5 = 90
In order to be relatively prime to 12, it can't have the factors 2 or 3. Let's try 5^2 x 7^2 x 11. 13475 has three prime factors, 18 divisors, and is relatively prime to 12.