t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9)
t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3)
so the factors of t4-81 are :(t2+9)(t+3)(t-3)
Hope this helps :-)
I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)
1, 3, 9, 27, 81.
1, 29
1, 31
They are: 2 and 11
2, 5, 10, 25
1, 2, 11 and 22
1, 7, 13, 91.
1, 3, 11, 33.
1, 3, 7, and 21 are.
Its prime factors are 2 and 3
1, 2, 4, 8, 16.
1, 2, 4, 31, 62, 124.
1, 2, 4, 5, 10, and 20