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Answered 2014-06-20 14:58:40

By using the quadratic equation formula or by completing the square

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you use the quadratic formula in math when the quadratic equation you are solving cannot be factored.


There are several methods for solving quadratic equations, although some apply only to specific quadratic equations of specific forms. The methods include:Use of the quadratic formulaCompleting the SquareFactoringIterative methodsguessing


You'll typically use it when solving a quadratic equation - when factoring isn't obvious.


In general, there are two steps in solving a given quadratic equation in standard form ax^2 + bx + c = 0. If a = 1, the process is much simpler. The first step is making sure that the equation can be factored? How? In general, it is hard to know in advance if a quadratic equation is factorable. I suggest that you use first the new Diagonal Sum Method to solve the equation. It is fast and convenient and can directly give the 2 roots in the form of 2 fractions. without having to factor the equation. If this method fails, then you can conclude that the equation is not factorable, and consequently, the quadratic formula must be used. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009) The second step is solving the equation by the quadratic formula. This book also introduces a new improved quadratic formula, that is easier to remember by relating the formula to the x-intercepts with the parabola graph of the quadratic function.


Solving for any variable in an equation differs from equation to equation. You can use various methods such as the quadratic formula, factoring, brute force algebra etc.ExampleSolve x in the the equation logx8=3/2 Answer(5(root(10)))/4


Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by factoring, using the square roots or quadratic formula. Solving quadratic equations by completing the square will always work when solving quadratic equations-You can also use division or even simply take a GCF, set the quantities( ) equal to zero, and subtract or add to solve for the variable


I guess you mean the standard quadratic equation, of the form ax^2 + bx + c = 0.There are three main algebraic methods, namely: * Factoring * Completing the square * Using the quadratic formula Since you want five, here are a few more, but they are usually not very convenient to use for this particular type of equation: * Trial and error * Graphic the equation * Diverse iterative methods, such as Newton's method, etc.


Here are some methods you can use:* Trial and error. This works especially well if the solution is a small integer. * Factoring. You must first write the equation in such a form that you have zero on the right. * Completing the square. * Using the quadratic formula. The last two methods work in all cases. The quadratic formula is easier to work with in the general case.


Simply learn and use the quadratic equation formula.


There is a new method, called Diagonal Sum Method, that quickly and directly give the 2 roots without having to factor the equation. The innovative concept of this method is finding 2 fractions knowing their sum (-b/a) and their product (c/a). It is fast, convenient and is applicable to any quadratic equation in standard form ax^2 + bx + c = 0, whenever it can be factored. If it fails to find answer, then the equation is not factorable, and consequently, the quadratic formula must be used. So, I advise you to proceed solving any quadratic equation in 2 steps. First, find out if the equation can be factored? How?. Use this new method to solve it. It usually takes fewer than 3 trials. If its fails then use the quadratic formula to solve it in the second step. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009)


Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.


u can use gauss jorden or gauss elimination method for solving linear equation u also use simple subtraction method for small linear equation also.. after that also there are many methods are available but above are most used


Finally, there are two methods to use, depending on if the given quadratic equation can be factored or not. 1.- The first one is the new Diagonal Sum Method, recently presented in book titled: "New methods for solving quadratic equations" (Trafford 2009). This method directly gives the two roots in the form of two fractions, without having to factor it. The innovative concept of this new method is finding 2 fractions knowing their product (c/a) and their sum (-b/a). This new method is applicable to any quadratic equation that can be factored. It can replace the existing trial-and-error factoring method since this last one contains too many more permutations. In general, it is hard to tell in advance if a given quadratic equation can be factored. However, if the new method fails to get the answers, then you can positively conclude that this equation can not be factored. Consequently, the quadratic formula must be used in solving. We advise students to always try to solve the given equation by the new method first. If the student gets conversant with this method, it usually take less than 2 trials to get answers. 2. the second one uses the quadratic formula that students can find in any algebra book. This formula must be used for all quadratic equations that can not be factored.


The most straightforward way to do this is to use the quadratic equation.


The Quadratic Equation is useful because you can't factorevery equation, so you use the quadratic equation. Even though it doesn't seem fun it is still useful.


To find the roots (solutions) of a quadratic equation.


You should always use the vertex and at least two points to graph each quadratic equation. A good choice for two points are the intercepts of the quadratic equation.



Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182Either use trial and error, or the quadratic formula, solving the following for x: x(x+1)=182


That the discriminant of the quadratic equation must be greater or equal to zero for it to have solutions. If the discriminant is less than zero then the quadratic equation will have no solutions.


You convert the equation to the form: ax2 + bx + c = 0, replace the numeric values (a, b, c) in the quadratic formula, and calculate.


It doesn't look as if you can solve this easily with factoring; you might try completing the square, or use the quadratic formula, with a = 1, b = 34, c = 56.Improved answer:Presumably this is a quadratic equation in the form of x2+34x = 56.Rearrange the equation in the form of:x2+34x-56 = 0Then by completing the square or using the quadratic equation formula the values of x will work out as:x = -17- the square root of 345or x = -17+ the square root of 345Your maths tutor should be familiar with the above methods of solving quadratic equations if you're not too sure.


The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.


In solving an inequality you generally use the same methods as for solving an equation. The main difference is that when you multiply or divide each side by a negative, you have to switch the direction of the inequality sign. The solution to an equation is often a single value, but the solution to an inequality is usually an infinite set of numbers, such as x>3.



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