201, 402, 603, 804, 1005, 1206. . .
The five multiples of 201 are 201,402,604,806,and 1008.Those are the first five multiples of 201,I got it by multiplying 201 by what # I needed.
3 x 67 = 201
201, 402, 603, 804, 1005.
67 of them because 67 times 3 = 201
28,140 and its multiples.
201, 402, 603, 804, 1005, 1206, 1407, 1608, 1809, 2010.
They can be: 51, 102, 153 and 201 which are 4 multiples of 51
201, 204, 207, 210, 213 and just keep adding three until you get to 300.
1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, 804.
Yes. 201/3 = 67 201/67 = 3 201/1 = 201 201/201 = 1
1, 2, 3, 6, 67, 134, 201, 402 1, 2, 3, 6, 67, 134, 201, 402
The odd multiples of 5 end with 5.If there is an even number of odd multiples of 5, their sum ends in 0, meaning their remainder when divided by 10 is 0;If there is an odd number of odd multiples of 5, their sum ends in 5, meaning their remainder when divided by 10 is 5.By "odd multiples of 5 from 1 to 2007 " do you mean:the multiples 1, 3, 5, ..., 2007 of 5?1 = 2 x 1 - 1, 3= 2 x 2 - 1, ..., 2007 = 2 x 1004 - 1 So there are 1004 multiples of 5, which is even so their sum has a remainder of 0 when divided by 10.the numbers between 1 and 2007 which are odd multiples of 5?1 ÷ 5 = 0.2 → first multiple of 5 in the range is 1 x 5 → the first odd multiple = 1 x 5 2007 ÷ 5 = 401.4 → last multiple of 5 in the range is 401 x 5 → the last odd multiple = 201 x 5401 = 2 x 201 - 1 which means there are 201 multiples of 5, which is odd so their sum has a remainder of 5 when divided by 10.As our number system is based on 10, the remainder when dividing by 10 gives the value of the units (last) digit of the original number.All even multiples of 5 end have a units digit of zero and do not affect the units digit of the sum when added; so the question could have included the even multiples of 5 (ie "What is the remainder when the multiples of five...") without changing the final answer.