n
n+1
n+2
n+3
n+4
A single number, such as 3461018, does not make a pattern.
He's at the top of HadesIsle, accessible from the outside, only during N1. There are five questions, which are relatively easy. To make life easier, save before starting his quiz, and through trial and error you'll get the N1 FolderA, which is widely regarded as the best N1 ExtraFolder for the N1 quarterfinals.
They are reverse operations, in the sense that if y is the square of x then x is a square root of y. Remember though, that in the above scenario, -x is also a square root of y.
n1= 25 n2= n1+1 n3= n1-1 n4=n1+2 n5=n1-2
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
The N1 is a rocket.
The pattern appears to be that n1 is defined as 25; n2 = n1 + 3; n3 = n2 - 4 = n1 - 1. If this is the pattern, the next number would be 25. If this is the pattern, the series would repeat endlessly: 25, 28, 24, 27,23, 26, 22, 25, , 28, 24, 27,23, 26, 22, ...
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
the value of the exponent n1
the value of the exponent n1
37