(1,head,head),(1,head,tail),(1,tail,head),(1,tail,tail)
(2,head,head), (2,head,tail),(2,tail,head),(2,tail,tail),
(3,head,head), (3,head,tail),(3,tail,head),(3,tail,tail),
(4,head,head), (4,head,tail),(4,tail,head),(4,tail,tail),
(5,head,head), (5,head,tail),(5,tail,head),(5,tail,tail),
(6,head,head), (6,head,tail),(6,tail,head),(6,tail,tail),
Two times the number of outcomes of the spin - which is not specified in the question.
Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8
There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
The possible outcomes of a coin that is flipped are heads or tails.
when you toss a coin three times, the total number of possible outcomes is
eight
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
The cube has 6 possible outcomes.The coin has 2 possible outcomes.There are 6 x 2 = 12 possible outcomes for a trialthat involves both the cube and the coin.
There are 6*6*2 = 72 possible outcomes.
Two times the number of outcomes of the spin - which is not specified in the question.
There are 25 = 32 possible outcomes.
If a coin is tossed 15 times there are 215 or 32768 possible outcomes.
There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.
In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.
the outcomes are 50:50.