55 and 57
The integers are 10 and 11.
There are no such integers.
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
Consecutive integers added or subtracted will turn out to be odd numbers. You can't make 8 with consecutive integers.
Let the first integer be n, then the following consecutive integer is (n+1) and: n + 3(n+1) = 35 → n + 3n + 3 = 35 → 4n = 32 → n = 8 → n+1 = 8 + 1 = 9 → The two integers s are 8 and 9.
12 and 13.
The integers are 10 and 11.
They are 5 and 6 because 5+(2*6) = 17
There are no such integers.
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
12 and 13.
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
10,12
Consecutive integers added or subtracted will turn out to be odd numbers. You can't make 8 with consecutive integers.
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6