Non-American nations typically use the metric system to denote the size of their ammunition, as does the US Military.
The 7.62mm round is equivalent to the .30 caliber round, which is 30-hundredths of an inch.
7.62 mm refers to the bullet diameter of the ammunition. It is commonly associated with the NATO standard round, 7.62x51mm (.308 Winchester), which is used in various military rifles and machine guns.
There are 10 mm in a cm, and 2.54 cm in an inch. Therefore, 7.62 mm equals .762 cm and .762 cm equals .3 inches. The answer is .3
mm-->in... divide by 25.4.... in-->mm... multiply by 25.4Direct Conversion Formula ____ mm*1 in25.4 mm=? in
1932. You are probably asking about the shell length, not caliber. A 16 gauge of this vintage was probably chambered for 2 9/16 inch (67.5 mm) shells but may have been modified to 2 3/4 (70 mm). I THINK all 12 gauge A5's had 2 3/4 inch chambers. A gunsmith probably wouldn't even charge you for measuring the chamber. Let him advise you on the use of steel or synthetic shot after he has examined the gun.
Yes, the calibre refers to the diameter of the bullet. Therefore, a 9mm would be smaller than a 10 mm.
205 mm = 8.070866 inches.Direct Conversion Formula 205 mm*1 in25.4 mm=8.070866142 in
762 mm
2.5 feet = 762 mm
762 mm
0.762meters
There are 10 mm in a cm, and 2.54 cm in an inch. Therefore, 7.62 mm equals .762 cm and .762 cm equals .3 inches. The answer is .3
76.2 cm
76.2 cm = 762 mm
30 mm = 1.18 inches (rounded)Direct Conversion Formula 30 mm*1 in25.4 mm=1.181102362 in
Roughly .275 or .28 caliber. Take MM divided by 25.4 (mm/inch) and you get caliber in hundredths of an inch.
9 caliber is 0.09 inch, smaller than any standard ammunition made. 0.09 inch = 2.286 mm. Perhaps you were thinking "What caliber is 9 mm?". 9 mm = 0.354 inch = 35.4 caliber.
.68 caliber is ABOUT 17mm.
1013 millibar or 762 mm of Mercury