It can be said to be exothermic since H is negative. Also below a temp of 3708ºC, the reaction will be spontaneous because ∆G will be negative. This is from ∆G = ∆H - T∆S.
Someone else answered this in more detail, but if you want an answer for apex, the answer is: "It is spontaneous at 2000k".
It can be said to be exothermic since H is negative. Also below a temp of 3708ºC, the reaction will be spontaneous because ∆G will be negative. This is from ∆G = ∆H - T∆S.
The reactants when methane burns in oxygen are methane and oxygen. The products are CO2, water and heat about 890 Kj/mole is given out. The equation is : CH4(g) + 2O2 _______> CO2 + 2H2O + Heat (-890 Kj/mole) When one mole of methane gas reacts with (burns in) 2 moles of oxygen gas we get 1 mole of carbon dioxide and 2 moles of water and 890 Kilo joules of heat is released. This reaction is exothermic as heat is released and a combustion reaction as methane gas is burned in free supply oxygen not limited supply otherwise carbon monoxide (CO) will be formed. Hope that helped you out. :-D
The ingredients are butane, isobutane, propane, and isopropane, PHE - 890.
The standard enthalpy of combustion for methane is -890 kJ/mol.
A thermochemical equation shows the amount of heat given out or taken in when the reaction occurs. CH4 + 2O2 = CO2 +2H2O, deltaH = -890 kJ/mol Note delta H is negative when heat is given out, exothermic and +ve when endothermic. Sorry can't do delta symbol - its a triangle!
It is spontaneous at 2000 K.
It can be said to be exothermic since H is negative. Also below a temp of 3708ºC, the reaction will be spontaneous because ∆G will be negative. This is from ∆G = ∆H - T∆S.
90% of 890= 90% * 890= 0.9 * 890= 801
880
It is 1000-110 = 890
12 x 890 = 10680 12% x 890 = 106.8
53.4 is 6% of 890. 890 + 53.4 = 943.4
12% of 890 is 106.8 Method: (12 × 890) ÷ 100 = 106.8
894 to the nearest 10 = 890
There are 89 tens in 890.
890
890 + 201 = 1091