-65
-17 and 3
-37
It means you need to multiply 7 by 14 and then add 1 to the answer.It means you need to multiply 7 by 14 and then add 1 to the answer.It means you need to multiply 7 by 14 and then add 1 to the answer.It means you need to multiply 7 by 14 and then add 1 to the answer.
When you multiple 17 by 3, you get 51. That is add 17 to itself for 3 times.
51
-51
-14 and -14 Add them together to get -28 Multiply them to get 196
The factor pairs of 51 are (51,1)(17,3) Even if you count their negative counterparts, none of them will add up to -16.
51
-51
51 > 0. Since the sum 14 is positive, the factors of 51 are both positive. The problem is that 51 = 3*17 and 3 + 17 = 20 ≠ 14. But we are lucky that 14 = 7 + 7. So wee can use the difference of the squares such as (7 - A)(7 + A) = 49 - A2 = 51, where -A2 = 2 = -(i√2)2 . Thus, the numbers are 7 - i√2 and 7 + i√2. or algebraically, x + y = 14; y = 14 - x xy = 51 x(14 - x) = 51 -x2 +14x = 51 x2 -14x = -51 x2 -14x + 72 = -51 + 49 (x - 7)2 = -2 x - 7 = ± √-2 x = 7 ± i√2
-14
Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.