a negro kettle.
the kettle boils and then the energy comes out as steam
-kettle -electric heater that's all i have! :)) When a current passes through a wire, the wire heats up. This is caused by the conversion of electrical energy into heat energy. /the heat produced depends on the resistance of the wire.
The amount of electricity it would take to boil a kettle would be phenomenal, regardless of whether the kettle is made from metal or plastic. I suggest instead you try boiling the water inside the kettle first.
By the fact that the kettle is hot. The heat energy is also warming the metal of the kettle. By the fact that the water boils to steam,; loss of water to steam. The energy should only heat the water to boiling point, and not heat the kettle nor allow the water to boil off.
The formula you are looking for is V = IR where V = Voltage I = Current R = Resistance With some formula manipulation and numbers plugged in you get I = 120V / 9.6Ω I = 12.5A The kettle would have 12.5 volts of current running through it.
yes it is because u don`t use current for it
Divide its power rating by its voltage rating. These ratings are found on its nameplate. For example, a 3-kW kettle rated at 230 V will draw a current of approx. 13 A.
A kettle does not have a magnetic force on its own. However, since it is metal, it can attract a magnet.
Plain Kettle Corn Chocolate Kettle Corn Slimey Kettle Corn Boiling Kettle Water Corn
The noun 'kettle' is a standard collective noun for:a kettle of hawksa kettle of vultures
A standard 3kW immersion heater will require a fuse rating of 13 A. This is because, it draws a current of 12 A.
the kettle does not react
kettle
metal kettle
The nursery rhyme character who put the kettle on is "Polly, put the kettle on."
Normal household current is AC not DC. If the kettle was DC what would it plug into? Actually, as a kettle is a purely resistive device it will perform equally well with a DC supply as with AC. Assuming you could plug it into a DC power source of the same voltage as it's AC supply it would boil water in approximately the same length of time.