Q: What describes the distance from the applied force to the fulcrum?

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On the side on which the force is being applied, the distance and force are directly proportional. On the other side of the lever, they are inversely proportional. If 1 pound of force is applied to a lever at 1 foot on the left side of the fulcrum, the lever will apply 1 pound of force 1 foot from the right side of the fulcrum. If 1 pound of force is applied 2 feet left of the fulcrum, the lever will apply 2 pounds of force 1 foot from the right side. If 1 pound is applied 4 feet left of the fulcrum, the lever will apply 4 pounds of force 1 foot to the right of the fulcrum. If 1 pound of force is applied 1 foot left of the fulcrum, at 2 feet on the right side, the force will be 1/2 pound. At four feet, it will be 1/4 pound. Etc,

If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.

A fulcrum is the turning point of a lever i.e. The hinge on a door. It is essential to know when learning about the law of the lever i.e. The distance from the fulcrum X force applied on the right hand side = The distance from the fulcrum X force applied on the left hand side. IF the lever is balanced. This can also be written as anticlockwise moments = clockwise moments.

False. A lever to multiply the force exerted has its fulcrum closer to the object than to the force is applied. This will increase the force but decrease the distance the object moves compared to the force end.

Fulcrum. Torque is the force applied to move the lever

Related questions

On the side on which the force is being applied, the distance and force are directly proportional. On the other side of the lever, they are inversely proportional. If 1 pound of force is applied to a lever at 1 foot on the left side of the fulcrum, the lever will apply 1 pound of force 1 foot from the right side of the fulcrum. If 1 pound of force is applied 2 feet left of the fulcrum, the lever will apply 2 pounds of force 1 foot from the right side. If 1 pound is applied 4 feet left of the fulcrum, the lever will apply 4 pounds of force 1 foot to the right of the fulcrum. If 1 pound of force is applied 1 foot left of the fulcrum, at 2 feet on the right side, the force will be 1/2 pound. At four feet, it will be 1/4 pound. Etc,

If the perpendicular distance from the point of application of the force to the fulcrum is x metres and the perpendicular distance from the crate to the fulcrum is y metres, then the force applied on the crate is 220*x/y N.

A fulcrum is the turning point of a lever i.e. The hinge on a door. It is essential to know when learning about the law of the lever i.e. The distance from the fulcrum X force applied on the right hand side = The distance from the fulcrum X force applied on the left hand side. IF the lever is balanced. This can also be written as anticlockwise moments = clockwise moments.

False. A lever to multiply the force exerted has its fulcrum closer to the object than to the force is applied. This will increase the force but decrease the distance the object moves compared to the force end.

The torque will be reduced. The torque is found by the cross product of the distance from the fulcrum and the applied force. Assuming the force is applied perpendicular to the lever, you merely multiply the two. So if the force applied remains constant and you shorten the distance to the fulcrum, you are reducing one of the values while the other remains constant. When multiplied, this will reduce the total. Therefore the torque will be reduced. In effect, the lever will have a weaker action.

Fulcrum. Torque is the force applied to move the lever

When we work with levers, we look at the lever and at the fulcrum. There are 4 variables in the scenario, and they are the force being applied on one side of the lever, and the force being applied on the other. Then there is the distance from the fulcrum that one force is being applied, and lastly the distance from the fulcrum to where the other force is being applied. The forces are Fr and Fe, and the distances from the fulcrum are Dr and De. (We often actually use F1, F2 and D1, D2.) If everything balances out and a static (stationary) condition exists, F1 x D1 = F2 x D2. (For your variables, Fr x Dr = Fe x De.) The products of the force on one side and distance from the fulcrum on that one side equals that same thing on the other side. Simple and easy.

Torque is calculated by multiplying a force by the distance from the fulcrum at which it acts.

Fulcrum

In the distance from the fulcrum to the input forcedivided by the distance from the fulcrum to theoutput force.

wow i just had a unit in science about this and i cant remember

No, that is 9x 2 = 18 N-m tryingto lift 9 x 3 = 27 N-m moment. The force x distance applied has to be greater