force of gravity between two objects is
F=GMN/R(SQUARE)
WHERE F IS THE FORCE , G IS THE UNIVERSAL GRAVITATION CONSTANT , M AND N ARE THE MASSES OF THE TWO BODIES AND R IS THE SHORTEST , PERPENDICULAR DISTANCE BETWEEN THE TWO BODIES
It's always in the general direction of the sun, with a small component to the left
or right of the sun depending on the present position of the moon and the other planets in the solar system.
force of attraction
It is attractive and increases if their masses increase.
When two objects get closer to each other increases the gravitational force between them increases.
It causes a pair of equal forces, one acting on each object
and directed toward the center of the other one.
Either increase the mass, or decrease the distance.
Toward the center of mass of the object
Towards the center of the Earth.
Gravitational force always attracts.
If he's moving with constant velocity, then the net force on him is zero. The force of gravity must be exactly balanced by the force of kinetic friction between him and the air.
The net force is zero.
Take north to be the positive direction, and south to be the negative direction. Net force = 13N + (-17N) = -4N Net force = 4N to the south.
You add them together. If there is no other force in the opposite direction it is also recognized as zero.
You can't, unless you know both of their directions. -- If they're in the same direction, then the net force is 10N in that same direction. -- If they're in opposite directions, then the net force is zero, and the direction doesn't matter because there's no net force. -- Depending on their directions, those two forces can combine to produce a net force of anything between zero and 10 N, in any direction. So you need to know their directions in order to figure out what the net force is.
-- A car accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the car. -- A stone accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the stone. -- A Frisbee accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the Frisbee. -- A baseball accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the baseball. -- A dog accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the dog. -- A book accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the book. -- A canoe accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the canoe. -- An airplane accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the airplane. -- A planet accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the planet. -- A cow accelerates in the direction of the net force on it, at a rate equal to the magnitude of the net force divided by the mass of the cow.
Newton's Second Law of Motion ...im pretty sure lol xD hope I helped!
The acceleration will be in the direction of the net force.
If he's moving with constant velocity, then the net force on him is zero. The force of gravity must be exactly balanced by the force of kinetic friction between him and the air.
The net force is zero.
An object will accelerate in the direction of net force
It is very easy to find the direction of net force exerted by Earth and Moon on a Space craft. Suppose Earth is at "0" point of 3-D coordinate system. Now say X1, Y1, Z1 are the coordinate of the Moon and X2, Y2, Z2 are the coordinates of Space craft. Now say M1, M2, and M3 are the mass of Earth, Moon and Space Craft respectively. Now calculate the gravitational force exerted by Earth and Moon separately in X,Y,Z directions. Now Vectorial SUM of the above force is the net force and resultant vector is the direction of net Gravitational force on the Space craft.
net force
Take north to be the positive direction, and south to be the negative direction. Net force = 13N + (-17N) = -4N Net force = 4N to the south.
Acceleration is proportional to net force.That means that acceleration is equal to (net force) times (something).The 'something' is [ 1 / (the mass of the object being accelerated by the force) ].
You add them together. If there is no other force in the opposite direction it is also recognized as zero.
They are both vector quantities and acceleration is in the direction of the net force.