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What distance increase is needed to reduce a sound's intensity from an initial 100dB to a final 80dB?
Wiki User
∙ 12y ago
Sound intensity is inversely proportional to the square of the distance
from the source.
-- Increase the distance from the source by 10 times.
-- Sound intensity decreases to 1/102 = 1/100 .
-- 10 log ( 1/100 ) = -20 dB
-- 100 dB - 20 dB = 80 dB
Wiki User
∙ 12y ago
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