A total of five coins.
30 cents
10 cents, but it also makes two shiny coins. Two nickels make up the value of a dime.
Each dollar is worth 100 cents; each nickel is worth five cents; each dime is worth 10 cents. You can put together any combination of nickels and dimes you like to make up one dollar.
two quarters, two dimes and a nickel: One half dollar, and one dime and two nickels
yes if the workers screwed up enough to make a dime/penny
If you don't have to use them all up, 36 people could get one dime apiece or 30 people could get 1 nickel and 1 dime. If you have to use them all up, 6 people could get 5 nickels and 6 dimes apiece. It's the GCF.
10 cents, but it also makes two shiny coins. Two nickels make up the value of a dime.
1 nickel = 5c 1 dime = 10c If 75c were all nickels then there would be 15 nickels. 2 nickels can then be changed for 1 dime and this can be done 7 times so that the final make up is 1 nickel and 7 dimes. There are thus 8 ways of producing 75c using just nickels and dimes.
Each dollar is worth 100 cents; each nickel is worth five cents; each dime is worth 10 cents. You can put together any combination of nickels and dimes you like to make up one dollar.
I am assuming this means what different combinations of coins would add up to 17 cents. You could have one dime, one nickel and 2 pennies, 1 dime, 7 pennies 3 nickels, 2 pennies 2 nickels, 7 pennies 1 nickel, 12 pennies 17 pennies
1 dime and 3 nickels
Seven combinations that I can come up with: two dimes a nickel and three pennies all pennies two dimes and eight pennies a quarter and three pennies five nickels and three pennies three nickels one dime and three pennies two nickels one dime and eight pennies
two quarters, two dimes and a nickel: One half dollar, and one dime and two nickels
Always finding nickels means that you need to lighten up a little. By lightening up you will have more. For instance, the dime: half the weight but twice the value. NUM3ER5... they're amazing!
yes if the workers screwed up enough to make a dime/penny
There must be at least one nickel, to account for the 5 cents of the 75 cents. So, one solution would be 1 nickel and 277 dimes. This would be (277 x 0.10) + 0.05 = 27.70 + 0.05 = 27.75 Another solution would be 1 dime and 553 nickels. This would be (553 x 0.05) + 0.10 = 27.65 + 0.10 = 27.75 You will have an odd number of nickels in an solution. Possible solutions include 1 nickel & 277 dimes 3 nickels & 276 dimes 5 nickels & 275 dimes 7 nickels & 274 dimes 9 nickels & 273 dimes up to 553 nickels and 1 dime
If you don't have to use them all up, 36 people could get one dime apiece or 30 people could get 1 nickel and 1 dime. If you have to use them all up, 6 people could get 5 nickels and 6 dimes apiece. It's the GCF.
The minimum number of quarters, pennies, and nickels needed to make up 123 cents is 4 quarters, 4 nickels, and 3 pennies.