3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
Yes, provided p = perimeter, b= breadth and h = height.
It is: 11h
Carbonic acid, H2CO3
3h + (2h 20m) + 35m = (3+2)h + (20+35)m = 5h + 55m
2h + 2h + 2h = 6h
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I-
(t+h)(x+2)
3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
2Si +2HF-2siF + 2H
Cl2 + 2H = 2HCl
h = 0.538462 14 + 5h + 2h = 5h + 28h 14 + 7h = 33h 14 + 7h - 7h = 33h - 7h 14 = 26h 14/26 = 26/26h 0..538462 = h
No because it equals zero.
Yes, provided p = perimeter, b= breadth and h = height.
I2 + 10 hno3 = 2 hio3 + 10 no2 + 4 h2o