It means that a chemical reaction has taken place, and copper sulfate, carbon dioxide, and water have combined somehow.
Then there would be an "equal" sign, and on the other side of the chemical equation would be another bunch of symbols for compounds, showing what chemicals came out of the reaction.
that aint right g
knov
Burning, oxidation.
Chances are the C and the H are together with multiple amounts. If so you'll get carbon dioxide (CO2) and water (H2O)
The anwer is 2 (C2H6) + 7(O2) =4 (CO2) + 6 ( H2O) left side : C=4 , H= 12, O=14 right side : C=4 , H= 12, O=14 so they are balanced.
cl2o7+h2o
h2o,Nacl,Co2,O2,O3
CuCO3 + H2SO4 -> CuSO4 + H2O + CO2 copper(II) carbonate + sulphuric acid -> copper(II) sulphate water + carbon dioxide
CO2 plus H2O makes club soda - which is not a combustion.
These are some possible ionic equation for CuSO4 plus H2O: Cu2+ + 6 H2O --> Cu(H2O)6 Cu(H2O)62+ + H2O <--> Cu(OH)(H2O)5+ + H3O+ This makes a solution of copper sulfate weakly acidic.
c2h5oh+h2o
This is not a decomposition reaction.
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
Na2CO3 (sodium carbonate) plus H2O (water) and CO2 (carbon dioxide) will undergo a chemical reaction to form sodium bicarbonate (NaHCO3). The balanced chemical equation for this reaction is: Na2CO3 + H2O + CO2 -> 2 NaHCO3.
The balanced equation is: 2 NH4Cl + Na2CO3 -> 2 NH3 + CO2 + 3 H2O + 2 NaCl
Reaction will result in gas (CO2) andsalt formation:copper(II) sulfate CuCO3 + SO42- + 2H+ --> CO2 +CuSO4+H2O
The "acid" form of CO2 and H2O is H2CO3, carbonic acid.
You mean balance it? 2C2H6 + 7O2 -> 4CO2 + 6H2O
H2O(aq)+CO2(g)