It means that at equilibrium the chemical reaction will mainly occur in the direction to the left of the chemical equation
eg 6co2 + 6H2o-----> c6h12o6
if equilibrium lies to left it means the dominating direction of the reaction will be to left ie co2 and h2o will be formed from c6h1206 ......hypothetically
you cant really tell if its strong like that. you need indicator liquid to tell you if its an acid or a base and then tell if its strong by seeing the reaction.
When a base is added to water and the equilibrium position shifts to the left, it means that the reaction is favoring the formation of the reactants rather than the products. This indicates that the base is not fully dissociating in water and the concentration of the reactants is higher than the products.
If Keq is less than 1, it indicates that the equilibrium lies to the left, favoring the reactants at equilibrium. This means that the forward reaction is less favored compared to the reverse reaction.
If the equilibrium constant (Kₑq) is greater than 1, it indicates that the concentration of products is higher than the reactants at equilibrium. This suggests that the forward reaction is favored and the equilibrium lies to the right, meaning more products are being formed.
A numerically large equilibrium constant (Keq) indicates that the equilibrium lies far to the right, with more products present at equilibrium than reactants. This means that the forward reaction is favored, leading to a higher concentration of products compared to reactants in the equilibrium state.
you cant really tell if its strong like that. you need indicator liquid to tell you if its an acid or a base and then tell if its strong by seeing the reaction.
When a base is added to water and the equilibrium position shifts to the left, it means that the reaction is favoring the formation of the reactants rather than the products. This indicates that the base is not fully dissociating in water and the concentration of the reactants is higher than the products.
If Keq is less than 1, it indicates that the equilibrium lies to the left, favoring the reactants at equilibrium. This means that the forward reaction is less favored compared to the reverse reaction.
In an irreversible equilibrium reaction, one direction of the reaction is favored over the other, resulting in a net consumption or production of reactants/products. The equilibrium position lies far to one side, with only minor changes occurring over time as the reaction proceeds to completion. These reactions typically have a large equilibrium constant (K) and are often driven by a large energy release or consumption.
It will take a short time to reach equilibrium It will take a long time to reach equilibrium The equilibrium lies to the right The equilibrium lies to the left Two of these One of those answers...
If the equilibrium constant (Kₑq) is greater than 1, it indicates that the concentration of products is higher than the reactants at equilibrium. This suggests that the forward reaction is favored and the equilibrium lies to the right, meaning more products are being formed.
In a system, unstable equilibrium occurs when a small disturbance causes the system to move further away from its original position, while stable equilibrium occurs when a small disturbance causes the system to return to its original position. The key difference lies in how the system responds to disturbances, with unstable equilibrium leading to further movement away from equilibrium and stable equilibrium leading to a return to equilibrium.
A numerically large equilibrium constant (Keq) indicates that the equilibrium lies far to the right, with more products present at equilibrium than reactants. This means that the forward reaction is favored, leading to a higher concentration of products compared to reactants in the equilibrium state.
The sign of ΔG° for the forward reaction is less than 0. The reactant could be a solid and the products could be gasses.
NH3 (ammonia) is considered a BL base because when in aqueous solution it produces the hydroxyl ion , OH-. The reaction looks like this: NH3 + H2O ==>NH4OH ==> NH4^+ + OH^-. Even though the equilibrium lies far to the left, their is sufficient OH- produced to make an alkaline solution.
Yes, ScOH3 (scandium hydroxide) is a weak base. It does not dissociate completely in water to release hydroxide ions, and its equilibrium lies more to the left, indicating a limited ability to accept protons.
An example of unstable equilibrium in sports is balancing on a balance beam in gymnastics. Athletes must continuously adjust their position to stay on the beam, as any slight movement can cause them to lose balance and fall off.