irregular shape! :D x x x x x x x x x x x x
How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
This would be a real bear to prove, mainly because it's not true.
You can prove by making two or more identical triangles.Congruence means when two figures have the same size, form, and shape.
A sheet of A4 paper could be classed as a plane 2D shape, as it has length x width. A shoebox is an example of a 3D shape, as it has length x width x depth.
it a shape the sides have names 5 sides = pent
irregular shape! :D x x x x x x x x x x x x
How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
This would be a real bear to prove, mainly because it's not true.
Let x be in A intersect B. Then x is in A and x is in B. Then x is in A.
How would you prove algebraically that the following function is one to one? f(x)= (x+3)^2 , x>= -3?
One could not. The shape could be a rectangle.
3D shape = length x width x height 2D shape = length x height
Prove all x px or all x qx then all x px or qx
You can prove by making two or more identical triangles.Congruence means when two figures have the same size, form, and shape.
A sheet of A4 paper could be classed as a plane 2D shape, as it has length x width. A shoebox is an example of a 3D shape, as it has length x width x depth.
You cannot, because the statements are false! (The second is rational only if r = 0).