1/24 = 1/16
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
3/8
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg
1/2 (50%) of them.
There is no possible answer. For any given fraction, half that fraction is another fraction and it will be closer to 0. And then half of that will be closer still, and then half of that ... . Hope you get the idea.
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
1 / 26 = 1 / 64.
Fraction remaining = 0.5^n where n = # of half lives that have elapsed60 yrs x 1 half life/12 yrs = 5 half lives have elapsed Fraction remaining = 0.5^5 = 0.03125 mass remaining = 0.03125 x 80.0 g = 2.5 g remaining
12.5% is remaining.
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
91.16% of the daughter product has formed after 3.5 half lives.
the half-life of chlorine 36 is 400,000 years. 200,000 years is 1/2 of a half life. in general, the formula to calculate the fraction of remaining amount is 1/2^n, where n represents the number of half-lives that have passed. in this case, n=1/2, or 0.5, therefore the remaining fraction is 1/2^0.5. Use your calculator and you will find that this is 0.707, or about 71% of the original amount. hope this helps
The fraction that remains is 1/8.
An eighth remains.
3/8
Iodine 131 is radioactive and has a half life of about 8 days. After 32 days there would be approximately 5 milligrams remaining
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg