The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
ans.
since, kinetic energy is given by the relation, k= mv2/2
velocity, v= (2km)1/2
If we double the kinetic energy (only) i.e. k, =2k, mass remaining the same, then the new velocity can be obtained by the above relation as,
v, = (2k,m)1/2 =(2*2k*m)1/2 =(2km)1/2 *(2)1/2 = v*21/2
i.e. v'/v = (2)1/2
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Thank you. The presentation is breathtaking in its erudition and its specificity.
The answer to the question is:
In order to double kinetic energy, you have to increase the speed
(magnitude of velocity) by 41.4 percent.
Kinetic energy= 1/2 mv2
So when v is doubled, kinetic energy increases by 22, that is by 4 times.
The Kinetic Energy would increase by a factor of 4, since : KE = 1/2mv^2
energy goes as velocity squared so it will quadruple energy (four times)
No. Kinetic energy is proportional to the square of the speed.
If the speed doubles, the KE increases by (2)2 = 4 times.
The square of 2 is 4. So, if the velocity doubles, the energy increases by a factor of 4.
The kinetic energy will also increase.
Kinetic Energy = (1/2)*(mass)*(velocity)2 If you double the mass, then the kinetic energy will double If you double the velocity, the kinetic energy will increase by a factor of 4
Kinetic energy is given by the following equaiton: KE = 0.5*m*v^2 Where KE is kinetic energy, m is the object's mass, and v is its velocity. In other words, an object's kinetic energy is dependent on its mass and the square of its velocity. Note that since the velocity term is squared, velocity has a larger effect on kinetic energy than mass. For example, if you double mass, the kinetic energy will also double, but if you double velocity, kinetic energy increases by a factor of four.
If the velocity of Earth were to double, it would have 4 times the kinetic energy. Twice the current kinetic energy would already be enough to catapult the Earth away from the Sun - never to return.
toaster
If the speed of an object doubles, its kinetic energy quadruples. This is because velocity is squared in the formula for kinetic energy.
Kinetic Energy = (1/2)*(mass)*(velocity)2 If you double the mass, then the kinetic energy will double If you double the velocity, the kinetic energy will increase by a factor of 4
Kinetic Energy increases as velocity increases. Kinetic Energy = 1/2 * Mass * Velocity2
Kinetic energy is given by the following equaiton: KE = 0.5*m*v^2 Where KE is kinetic energy, m is the object's mass, and v is its velocity. In other words, an object's kinetic energy is dependent on its mass and the square of its velocity. Note that since the velocity term is squared, velocity has a larger effect on kinetic energy than mass. For example, if you double mass, the kinetic energy will also double, but if you double velocity, kinetic energy increases by a factor of four.
If the velocity of Earth were to double, it would have 4 times the kinetic energy. Twice the current kinetic energy would already be enough to catapult the Earth away from the Sun - never to return.
8
toaster
as you decrease the velocity of a car, you decrease the kinetic energy.
If the speed of an object doubles, its kinetic energy quadruples. This is because velocity is squared in the formula for kinetic energy.
The kinetic energy increases as the velocity increases (KE = 1/2mv2) until terminal velocity is reached, at which point the velocity becomes constant, and kinetic energy will no longer increase. The potential energy and kinetic energy will be at equilibrium, where PE = -KE.
particles speed up.
it speeds up
Kinetic energy is determined by mass and velocity. The velocity is halved if you double the original mass, so the kinetic energy stays the same (unless the mass added has the same kinetic energy in the observer's reference frame as the original mass).