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Since you are reducing the distance between the charges by 7 times, hence the new force b/w the charges will be 49 times the electric force between the charges in the previous condition.

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13y ago
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11y ago

The electrostatic force is multiplied by the factor of 1/52 = 1/25.
It becomes 4% of what it was before the move.
Just like gravity.

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Q: What happens to the electric force between two charges if you increase the distance between them by a factor of 5?
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Two point charges q1 and q2 are located a distance r apart in a vacuum Which change to the charges will halve the magnitude of the electric charge between them?

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How does distance effect the electric force between two objects?

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