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If the distance between two objects is quadrupled, the force between them decreases to one sixteenth (1/16) of its original value. This relationship is described by the inverse square law, which states that the force between two objects is inversely proportional to the square of the distance between them.
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What happens to the electrostatic force if one charge is quadupled?
If one charge is quadrupled, the electrostatic force between the charges will increase by a factor of 4. This is because the electrostatic force is directly proportional to the product of the two charges involved.
What happens to the gravitational force between two objects as the distance between them is quadrupled?
Gravitational force is inversely proportional to the square of the distancebetween the objects.1/42 = 1/16The force becomes 1/16 of what it was originally. That's 93.75% less.
What happens to the distance over which you exert your force?
The amount of force you exert remains the same, but the distance over which you exert the force can affect the work done. If you exert a force over a longer distance, you may do more work because the force acts over a greater distance. If the distance over which you exert the force is shorter, the work done may be less.
What happens to a force when the distance increases?
When the distance between objects increases, the force between them decreases. This relationship is described by the inverse square law, meaning that the force decreases as the square of the distance between the objects increases.
When doing wwork with a simple machine what happens when the effort distance is increased?
When the effort distance on a simple machine is increased, it allows for less force to be applied to achieve the same work output. This happens because the work done is a product of force and distance, thus increasing the effort distance decreases the force required.
What happens to the electrostatic force if one charge is quadupled?
If one charge is quadrupled, the electrostatic force between the charges will increase by a factor of 4. This is because the electrostatic force is directly proportional to the product of the two charges involved.
What happens to the gravitational force between two objects as the distance between them is quadrupled?
Gravitational force is inversely proportional to the square of the distancebetween the objects.1/42 = 1/16The force becomes 1/16 of what it was originally. That's 93.75% less.
What happens to the circumference of the circle when the diameter is quadrupled?
The circumference is also quadrupled.
When the distance between two charges is halved the electric force between the charges?
The forces in each direction are quadrupled.
What happens to the perimeter of a rectangle when its length and width are quadrupled?
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
What happened to the force between two charges if the distance between them is out in half?
The force is quadrupled; f= k/r2 goes to f=k/(r/2)2 = 4k/r2
What happens to the circumference of a circle when the radius is quadrupled?
It gets bigger.
What happens to the distance over which you exert your force?
The amount of force you exert remains the same, but the distance over which you exert the force can affect the work done. If you exert a force over a longer distance, you may do more work because the force acts over a greater distance. If the distance over which you exert the force is shorter, the work done may be less.
What happens to the gravitational force if distance increases?
It decreases[:
What happens to the volume of a rectangular prism if two dimensions are doubled?
The volume is quadrupled.
What happens to the area of a parallelogram when you double the height and the base?
The area of the parallelogram is quadrupled.
What happens to the force between two charges if the distance between them is quadrupled?
The new force between the two objects will be 1/16 of what the original force was.This relationship can be found by using this equation:F=(kQ1Q2)/r2In this case "r" represents the distance between the two charges, the "Q"s represent the two charges, the "k" represents Coulomb's constant, and "F" is the force.Since "r" increased by a factor of 4 in the problem, and (4r)2 equals 16r2, then the "new" Force (Fn) is proportional to 1/16r2. You can use proportionality to set up the equation 16Fn = Fo where Fn is the new force and Fo is the original force. If you divide both sides by 16 to solve for Fn, you come up with the fact that the "new" force equals the original force over 16, which demonstrates that the "new" force is 1/16 of the original.
