the mass of the balloon increases because the size of the balloon has increased. :)
The gas will expand as it is heated.
it becomes low
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v
the heat makes the molecules inside the balloon travel faster, pushing outward on the balloon. This, the balloon expands when heated
Because as the balloon is heated, the gases on the inside of the balloon begin to expand and press out on the walls of balloon. If a balloon is refridgerated, the opposite is true: the gases on the inside of the balloon will begin to contract, causing the balloon to shrink.
they pop
The gas will expand as it is heated.
When the air is heated inside the balloon, it expands, causing it to be lighter than the surrounding (and presumably) cooler air. One imagines however, that as the air inside the balloon is heated, some air is forced out (due to expansion), thus resulting in a decrease in the entire apparatus' overall mass (not to mention a decrease in mass due to any fuel's having been used to heat the air in the balloon).
it becomes low
It is reduced by haft
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
The density decreases by half. You find the answer by knowing that density is equal to mass divided by the volume. If the mass stays constants and the volume is doubled, then the density is halved.
it will decrease
A chemical reaction in a hot air balloon can be when the propane is heated up. That is a chemical reaction because something has heated up.
The atoms in the mass become more energetic and create more pressure. If the bounds of the container allows it, such as in a balloon, the gas will expand. If the bounds doe not allow it, such as in a fixed container, the pressure will increase.