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If you apply the same pressure to both ports, then the piston will move. This is because the areas of the piston are different, due to the piston rod on one side. The force on the large area will be P x A1 and the opposing force will be P x A2, where A2 is less than A1 by the area of the piston rod. The resultant force will be P x (A1-A2).

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Q: What happens when pressure is applied to both ports on a hydraulic cylinder?
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