You get a mixture of sodium chloride and gold. There will be no chemical reaction. Gold is very unreactive.
To separate gold from sodium gold chloride, you can use a process called electrolysis. In this process, an electric current is passed through the solution, causing the gold to plate out onto the cathode while the sodium remains in the solution. The plated gold can then be removed and further refined.
FeCI3 +3NaOH ->Fe(OH)3 +3NaCIIron (III) chloride + Sodium Hydroxide ---> iron (III) hydroxide + sodium chloride
Suitable substances for electrodes in a sodium chloride aqueous solution include platinum, gold, or graphite. These materials are chemically inert and do not react with the electrolyte solution, ensuring accurate measurements during experiments.
1st dilute A c with 2parts water let sit so clorine evaporats 2nd use supersatured solution of sodiummetabisulfite (smb) 3rd add smb to auric chloride a little at a time and let stand as gold oxide presipatates out of solution now the brown at the bottom is gold oxide next amalgamate with borax and lots of heat voala shyknee gold stuff
The ionic formula for gold chloride is AuCl3. This indicates that one gold ion (Au3+) combines with three chloride ions (Cl-) to form the compound gold chloride.
To separate gold from sodium gold chloride, you can use a process called electrolysis. In this process, an electric current is passed through the solution, causing the gold to plate out onto the cathode while the sodium remains in the solution. The plated gold can then be removed and further refined.
FeCI3 +3NaOH ->Fe(OH)3 +3NaCIIron (III) chloride + Sodium Hydroxide ---> iron (III) hydroxide + sodium chloride
Gold(III) chloride
Gold is reduced. Gold is plated onto the cathode.
gold (Ag) is a pure element, so the electrons just orbit the nucleus in the electron cloud. But salt is a compound of sodium plus chloride (NaCl). these elements are bonded together in an Ionic bond, so Sodium (Na) loses an electron, and that electron is transferred to chloride (Cl), this way both elements have 8 valence electrons. In short, gold's electrons orbit the nucleus, and in salt, sodium gives an electron to chloride so they can both have 8 valence electrons.
Most commonly it is AuCl3 for gold(III) chloride. Gold(I) chloride would be AuCl.
In the case of NaCl.the valency of sodium and chloride is two.so you dont have to specify it.but where as in Icl the valency different so you call it as iodine monochloride.to denote the presence of single chloride atom. Sodium chloride is an ionic compound, so you don't write 'mono' 'di' 'tri' etc. in the name. MgCl2 would simply be magnesium chloride, not magnesium dichloride. Covalent compounds such as ICl sometimes have 'mono' 'di' or 'tri' in their name, but ionic compounds don't. == == == == == ==
Suitable substances for electrodes in a sodium chloride aqueous solution include platinum, gold, or graphite. These materials are chemically inert and do not react with the electrolyte solution, ensuring accurate measurements during experiments.
Gold and silver are elements. The symbol for gold is Au, and the symbol for silver is Ag.
Gold (I) Chloride.
doesn't create gold, turns bluish though
1st dilute A c with 2parts water let sit so clorine evaporats 2nd use supersatured solution of sodiummetabisulfite (smb) 3rd add smb to auric chloride a little at a time and let stand as gold oxide presipatates out of solution now the brown at the bottom is gold oxide next amalgamate with borax and lots of heat voala shyknee gold stuff