The answer is: a lever.
A lever is a simple machine that has a stick that pivots at a point called a Fulcrum.
There are 3 types of Lever:
First class lever: A first class lever is when a fulcrum is in the middle of the input force and the load. An example is a seesaw in the playground. When you press down the side of seesaw,(input force) the other side goes up. (load, output force) In the middle, there is a fixed point.
Second class lever: A second class lever is where you have the load in the middle of the Fulcrum and the input force. An example would be a wheelbarrow. The basket in the middle is the load( also called the output force) the wheel at the end is the Fulcrum, and the handle that you press up and down is the input force.
Third class lever: A third class lever is a lever that has a input force in between the Fulcrum and the Load. An example is a Hammer. The sharp part is the load(output force) the part you grab and swing is the input force, and the other end of the hammer is the Fulcrum.
It has a pivot point
A Lever comprises of three components:Fulcrum or Pivot - the point about which the lever rotatesLoad or Resistance - the object that requires movingEffort - the force applied by the user of the lever system
distance over which the force is applied ________________________________ Distance over which the load was moved or MA= Effort Force _________ Load force OR MA= Length of Load arm ____________________X Weight/mass Length of Effort arm
No. It's a second class lever. A 1st class one has the pivot in the centre.
A stiff rod that rotates around a pivot point is called a lever. It is a type of simple machine that is used to help move a heavy or firmly fixed load.
The force a lever can apply to a given point greatly depends on two distances:The distance from the pivot point to the object to be lifted and the distance from the pivot point to the point on the lever where force will be applied.To reduce the distance from the pivot-point to the point where Force is applied is to reduce the "force" of a lever.
a pivot is the midle point
Torque is defined as the product of the distance from the pivot point, times a force, times an angle function. If any of the three factors is zero, the product is zero. In this case, the distance from the pivot point.
The fulcrum is the fixed point or pivot around which a lever rotates or moves. It is the point where the input force is applied to the lever to create movement or lift an object.
The pivot point (or more precisely the "apparent pivot point") is that point along the fore and aft axis of a turning ship, that has no sideways movement, having for reference the surface of the water. The pivot point is generally at 1/3 ship's length from the bow when the ship is moving ahead, and between ¼ ship's length from the stern and the rudder post when going astern. But if a powerful and effective lateral force is applied at one end of the vessel, the position of the pivot point will shift at about 1/3rd ship's length from the other end of the ship (relative to the applied force).
Torque is defined as a measure of how much a force acting on an object causes that object to rotate. The object rotates about an axis, which is called the pivot point. Let the force acting on it is 'F'. The distance from the pivot point to the point where the force acts is called the moment arm, and is denoted by 'r'.Now, torque, τ = r * F = rFsin ѲHence, torque is the cross product between the distance vector (the distance from the pivot point to the point where force is applied) and the force vector, 'a' being the angle between r and F. We are taking cross product because the variables involved are vectors. Note that the distance in this case is a vector.
let the input force be F1,and the distance between point of application of input force and the lever point is x1,similarly if output force iis F2,and distance of it's point of apllication is x2,then efficiency of the lever is (F2*x2)/(F1*x1) actually F*x gives the work done,and efficiency of any machine is output work/input work
You should apply a force equal to 20N in the opposite direction of the 10N force 5 meters away from the pivot point.
The way torque works, these two cases give the same torque, or twisting force, to the object at the pivot point. To find the torque applied, multiply the force by the distance. Obviously this is the same in the two cases you describe.
it is called the "center"
That's going to depend on -- the radius from the center to the point where the input force is applied, -- the angle in the plane of the wheel between the direction of the force and the radius to it, and -- the radius from the center to the point where the output force is measured. None of that information is included in the question, so nobody is in a position to speculate on an answer yet.
It is the radius