Well, first of all, protons don't make light. I think you mean 'photons'.
A photon of ultraviolet light carries more energy than a photon of visible light,
because it has a higher frequency / shorter wavelength.
I think you have phrased this question wrong as a photon is a single packet of energy that we call light and it is what wavelenth the particles are at that determine where it is on the elecromagnetic spectrum. So in answer to your question a Ultraviolet BEAM of photons has a higher WAVELEGNTHthan a infared beam of photons.
Each individual photon of visible light is less energetic than any individual photon of ultraviolet light.
tl;dr: Less.
Ultraviolet light has much more energy than infrared.
From that list of choices, the ultraviolet photon is the most energetic.
Ultraviolet ...
the higher the frequency the higher the energy.
The UV photon has more than double the frequency,
so has has more than double the energy.
ultrviolet radiation
Yes they do.
Of course ultra violet.
not possible, as visible light photons have less energy and ultraviolet photons need more energy. Energy can neither be created nor be destroyed. So by conservation principle ultraviolet photon as they fall on fluorescent material could give out less energetic light photons, but the converse is not possible.
Infra-red has less energy the visible light, and so it takes less energy to create.
No. X-Rays have a greater frequency than visible light. In order of increasing frequency(or decreasing wavelength). Radio waves, Microwaves, Infra-red radiation, Visible light, Ultraviolet radiation, X-rays, Gamma rays.
UV photons have more energy (less wavelength, higher frequency) than visible light photons. It is possible to convert photons to ones with less enery, but not the opposite.
Visible light and other waves are part of the electromagnetic spectrum. These waves unlike sound waves can travel through vacuums and do so at c (3x10^8 m/s). The spectrum is very broad and includes microwaves, ultraviolet , x-rays, and our own visible light spectrum. These waves are differentiated based on their frequency but all contain photons, mass-less charge-less particles, hence the dual nature of light (light and other waves behave both as particles and waves, confusing i know :P) basically what this means is that the only difference between visible light, x-rays, and microwaves is the frequency of the photon wave.
not possible, as visible light photons have less energy and ultraviolet photons need more energy. Energy can neither be created nor be destroyed. So by conservation principle ultraviolet photon as they fall on fluorescent material could give out less energetic light photons, but the converse is not possible.
Wavelength of violet is the shortest and that for red is the longest in the visible region. So for ultra violet the wavelength is to be less still and that for infra red it has to be larger than red So wavelength increases as we move through UV, visible and IR.
More energy per photon than visible light, if that's what you mean.
Less than that of visible light. The Wikipedia lists a wavelength between about 100 and 310 nm.
Yes. Radiations on the "red" end of the spectrum, such as radio, microwave, and infrared, have markedly less energy than visible light. Frequencies on the "purple" end, on the other hand, such as ultraviolet, x-ray, and gamma, have considerably more.
Infra-red has less energy the visible light, and so it takes less energy to create.
Radio waves; microwaves; infrared; visible light; ultraviolet; Roentgen rays (a.k.a. X-rays); gamma rays.Radio waves; microwaves; infrared; visible light; ultraviolet; Roentgen rays (a.k.a. X-rays); gamma rays.Radio waves; microwaves; infrared; visible light; ultraviolet; Roentgen rays (a.k.a. X-rays); gamma rays.Radio waves; microwaves; infrared; visible light; ultraviolet; Roentgen rays (a.k.a. X-rays); gamma rays.
Yes, it does. UV-C wavelength is 200-280 nanometers, UV-B is 280-320 nm, and UV-A is 320-400nm.
Infrared radiation has less energy (per photon) than visible light.
No. X-Rays have a greater frequency than visible light. In order of increasing frequency(or decreasing wavelength). Radio waves, Microwaves, Infra-red radiation, Visible light, Ultraviolet radiation, X-rays, Gamma rays.
UV photons have more energy (less wavelength, higher frequency) than visible light photons. It is possible to convert photons to ones with less enery, but not the opposite.
Visible light and other waves are part of the electromagnetic spectrum. These waves unlike sound waves can travel through vacuums and do so at c (3x10^8 m/s). The spectrum is very broad and includes microwaves, ultraviolet , x-rays, and our own visible light spectrum. These waves are differentiated based on their frequency but all contain photons, mass-less charge-less particles, hence the dual nature of light (light and other waves behave both as particles and waves, confusing i know :P) basically what this means is that the only difference between visible light, x-rays, and microwaves is the frequency of the photon wave.