You can easily factor this:2x2 + 3x = 0x(2x + 3) = 0Separate this into two equations, one for each solution:x = 02x + 3 = 02x = -3x = -3/2So the two solutions are 0, and -3/2.You can easily factor this:2x2 + 3x = 0x(2x + 3) = 0Separate this into two equations, one for each solution:x = 02x + 3 = 02x = -3x = -3/2So the two solutions are 0, and -3/2.You can easily factor this:2x2 + 3x = 0x(2x + 3) = 0Separate this into two equations, one for each solution:x = 02x + 3 = 02x = -3x = -3/2So the two solutions are 0, and -3/2.You can easily factor this:2x2 + 3x = 0x(2x + 3) = 0Separate this into two equations, one for each solution:x = 02x + 3 = 02x = -3x = -3/2So the two solutions are 0, and -3/2.
2x2 + 3x - 5 = 02x2 - 2x + 5x - 5 = 02x(x - 1) + 5(x - 1) = 0(x - 1)(2x + 5) = 0x - 1 = 0 or 2x + 5 = 0x = 1 or x = -5/2
f(x) = x2 + 5x + 6At a critical point, f'(x) = 0.f'(x) = 2x + 5 = 02x = -5x = -2.5f(-2.5) = (-2.5)2 + 5(-2.5) + 6 = (6.25) - (7.5) + (6) = 4.75
2x2 + 15 = 11x ? Can be only for some values of x.2x2 + 15 = 11x subtract 11x to both sides2x2 - 11x + 15 = 0(2x - 5)(x - 3) = 02x - 5 = 0 or x - 3 = 0x = 5/2 or x = 3
y = x2 + 12x + 21At the max or min point, the first derivative of the function = 0.2x + 12 = 02x = -12x = -6
5x - 16 = 3x2x - 16 = 02x = 16x = 8
Note that the reason there exists a technique called multiplication is so that we do not have to perform tedious and lengthy series of addition such as the one you have presented. So, you have given us 24 of the number 5 to add. 24 x 5 = 120. (Addition form) 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 120
Thirty
5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 55
4 + 6 + 6 + 5 + 5 + 4 + 6 + 5 + 5 + 6 + 5 + 5 + 5 + 3 = 70
5 + 5 + 5 + 5 + 5 + 5 = 30
5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 45, the shorter version is 5*9.